I am doing basic http auth with the HttpURLConnection
object in Java.
URL urlUse = new URL(url);
HttpURLConnection conn = null;
In addition, if you wish to parse your object in case of http error (400-5** codes), You can use the following code: (just replace 'getInputStream' with 'getErrorStream':
BufferedReader rd = new BufferedReader(
new InputStreamReader(conn.getErrorStream()));
StringBuilder sb = new StringBuilder();
String line;
while ((line = rd.readLine()) != null) {
sb.append(line);
}
rd.close();
return sb.toString();
This function will be used get the data from url in form of HttpResponse object.
public HttpResponse getRespose(String url, String your_auth_code){
HttpClient client = new DefaultHttpClient();
HttpPost postForGetMethod = new HttpPost(url);
postForGetMethod.addHeader("Content-type", "Application/JSON");
postForGetMethod.addHeader("Authorization", your_auth_code);
return client.execute(postForGetMethod);
}
Above function is called here and we receive a String form of the json using the Apache library Class.And in following statements we try to make simple pojo out of the json we received.
String jsonString =
EntityUtils.toString(getResponse("http://echo.jsontest.com/title/ipsum/content/ blah","Your_auth_if_you_need_one").getEntity(), "UTF-8");
final GsonBuilder gsonBuilder = new GsonBuilder();
gsonBuilder.registerTypeAdapter(JsonJavaModel .class, new CustomJsonDeserialiser());
final Gson gson = gsonBuilder.create();
JsonElement json = new JsonParser().parse(jsonString);
JsonJavaModel pojoModel = gson.fromJson(
jsonElementForJavaObject, JsonJavaModel.class);
This is a simple java model class for incomming json. public class JsonJavaModel{ String content; String title; } This is a custom deserialiser:
public class CustomJsonDeserialiserimplements JsonDeserializer<JsonJavaModel> {
@Override
public JsonJavaModel deserialize(JsonElement json, Type type,
JsonDeserializationContext arg2) throws JsonParseException {
final JsonJavaModel jsonJavaModel= new JsonJavaModel();
JsonObject object = json.getAsJsonObject();
try {
jsonJavaModel.content = object.get("Content").getAsString()
jsonJavaModel.title = object.get("Title").getAsString()
} catch (Exception e) {
e.printStackTrace();
}
return jsonJavaModel;
}
Include Gson library and org.apache.http.util.EntityUtils;
Define the following function (not mine, not sure where I found it long ago):
private static String convertStreamToString(InputStream is) {
BufferedReader reader = new BufferedReader(new InputStreamReader(is));
StringBuilder sb = new StringBuilder();
String line = null;
try {
while ((line = reader.readLine()) != null) {
sb.append(line + "\n");
}
} catch (IOException e) {
e.printStackTrace();
} finally {
try {
is.close();
} catch (IOException e) {
e.printStackTrace();
}
}
return sb.toString();
}
Then:
String jsonReply;
if(conn.getResponseCode()==201 || conn.getResponseCode()==200)
{
success = true;
InputStream response = conn.getInputStream();
jsonReply = convertStreamToString(response);
// Do JSON handling here....
}
The JSON string will just be the body of the response you get back from the URL you have called. So add this code
...
BufferedReader in = new BufferedReader(new InputStreamReader(
conn.getInputStream()));
String inputLine;
while ((inputLine = in.readLine()) != null)
System.out.println(inputLine);
in.close();
That will allow you to see the JSON being returned to the console. The only missing piece you then have is using a JSON library to read that data and provide you with a Java representation.
Here's an example using JSON-LIB
You can get raw data using below method. BTW, this pattern is for Java 6. If you are using Java 7 or newer, please consider try-with-resources pattern.
public String getJSON(String url, int timeout) {
HttpURLConnection c = null;
try {
URL u = new URL(url);
c = (HttpURLConnection) u.openConnection();
c.setRequestMethod("GET");
c.setRequestProperty("Content-length", "0");
c.setUseCaches(false);
c.setAllowUserInteraction(false);
c.setConnectTimeout(timeout);
c.setReadTimeout(timeout);
c.connect();
int status = c.getResponseCode();
switch (status) {
case 200:
case 201:
BufferedReader br = new BufferedReader(new InputStreamReader(c.getInputStream()));
StringBuilder sb = new StringBuilder();
String line;
while ((line = br.readLine()) != null) {
sb.append(line+"\n");
}
br.close();
return sb.toString();
}
} catch (MalformedURLException ex) {
Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
} catch (IOException ex) {
Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
} finally {
if (c != null) {
try {
c.disconnect();
} catch (Exception ex) {
Logger.getLogger(getClass().getName()).log(Level.SEVERE, null, ex);
}
}
}
return null;
}
And then you can use returned string with Google Gson to map JSON to object of specified class, like this:
String data = getJSON("http://localhost/authmanager.php");
AuthMsg msg = new Gson().fromJson(data, AuthMsg.class);
System.out.println(msg);
There is a sample of AuthMsg class:
public class AuthMsg {
private int code;
private String message;
public int getCode() {
return code;
}
public void setCode(int code) {
this.code = code;
}
public String getMessage() {
return message;
}
public void setMessage(String message) {
this.message = message;
}
}
JSON returned by http://localhost/authmanager.php must look like this:
{"code":1,"message":"Logged in"}
Regards