How do you create pretty json in CHEF (ruby)

Question

How would you make an erb template that has human readable json?

The following code works, but it makes a flat json file

default.rb

default[\'         


        

Answer 1

As pointed out by this SO Answer .erb templates are great for HTML, and XML, but is not good for json.

Luckily, CHEF uses its own json library which has support for this using .to_json_pretty

@coderanger in IRC, pointed out that you can use this library right inside the recipe. This article shows more extensively how to use chef helpers in recipes.

default.rb

# if ['foo']['bar'] is null, to_json_pretty() will error
default['foo']['bar'] = {}

recipe/foo.rb

pretty_settings = Chef::JSONCompat.to_json_pretty(node['foo']['bar'])

template "foo.json" do
  source 'foo.json.erb'
  variables :settings => pretty_settings
  action :create
end

---

Or more concise as pointed out by YMMV

default.rb

# if ['foo']['bar'] is null, to_json_pretty() will error
default['foo']['bar'] = {}

recipe/foo.rb

template "foo.json" do
  source 'foo.json.erb'
  variables :settings => node['foo']['bar']
  action :create
end

templates/foo.json.erb

<%= Chef::JSONCompat.to_json_pretty(@settings) %>

Answer 2

Something like this would also work:

file "/var/my-file.json" do
  content Chef::JSONCompat.to_json_pretty(node['foo']['bar'].to_hash)
end

Answer 3

<%= Chef::JSONCompat.to_json_pretty(@settings) %> Works like Charm !!