Mongoose.js: Find user by username LIKE value

Question

I like to to go find a user in mongoDb by looking for a user called value. The problem with:

username: \'peter\'

is that i dont find it if

Answer 1

For those that were looking for a solution here it is:

var name = 'Peter';
model.findOne({name: new RegExp('^'+name+'$', "i")}, function(err, doc) {
  //Do your action here..
});

Answer 2

db.users.find( { 'username' : { '$regex' : req.body.keyWord, '$options' : 'i' } } )

Answer 3

I had problems with this recently, i use this code and work fine for me.

var data = 'Peter';

db.User.find({'name' : new RegExp(data, 'i')}, function(err, docs){
    cb(docs);
});

Use directly /Peter/i work, but i use '/'+data+'/i' and not work for me.

Answer 4

if I want to query all record at some condition，I can use this:

if (userId == 'admin')
  userId = {'$regex': '.*.*'};
User.where('status', 1).where('creator', userId);

Answer 5

You should use a regex for that.

db.users.find({name: /peter/i});

Be wary, though, that this query doesn't use index.

Answer 6

mongoose doc for find. mongodb doc for regex.

var Person = mongoose.model('Person', yourSchema);
// find each person with a name contains 'Ghost'
Person.findOne({ "name" : { $regex: /Ghost/, $options: 'i' } },
    function (err, person) {
             if (err) return handleError(err);
             console.log('%s %s is a %s.', person.name.first, person.name.last, person.occupation);
});

Note the first argument we pass to mongoose.findOne function: { "name" : { $regex: /Ghost/, $options: 'i' } }, "name" is the field of the document you are searching, "Ghost" is the regular expression, "i" is for case insensitive match. Hope this will help you.