Preventing react from rendering unchanged componets into the virtual DOM

后端 未结 1 1851
醉梦人生
醉梦人生 2021-02-09 16:30

I have written a simple treeview in typescript using react to render the DOM.

Every node has to follow the simple interface.

interface INode {
    label:         


        
相关标签:
1条回答
  • 2021-02-09 17:12

    Improving ReactJS rendering performance

    First off, don't spend time on this unless you see the need for it in your application. Checking against virtual DOM is a pretty cheap operation. If, however, you need to optimize your app, there are a few tactics to achieve this.

    Preventing react from rendering unchanged componetns into the virtual DOM (like you asked)

    There are two broad approaches to doing this:

    • Not re-rendering a component that will produce the same output
    • Not applying changes to component unless it's changed

    Not re-rendering a component that will produce the same output

    You can avoid re-rendering using shouldComponentUpdate. To make shouldComponentUpdate more efficient, you can use frameworks to ensure you only have immutable objects in state, or you can simply make a habit of not mutating objects, but rather creating new ones. See React Immutability Helpers. That will allow you to do a shallow check when comparing nextState and nextProps to current state and props (can be done easily with shallowCompare).

    Not applying non-changes to the component

    This means only updating state or props if the new values are different from the current values. This approach is not brought forth as often, but I feel it has deserves some merit.

    State: Only do setState({ value: newValue }) if newValue !== this.state.value. This can be achieved in multiple ways, but one way is to actually make the check before you do setState().

    Props: If non-changes come from props, it's typically because the parent component holds a value (in it's state) that is passed to one of it's other children as a prop. The parent component then needs to re-render itself and all of it's children. If you only want the components that depend on the value to change, you can have the components listen a part of a global app state and inject only what is useful for that component. That way, the value will be passed directly to those components who are interested in it, and no other components will be re-rendered.

    (This removes the need to store the state in a common parent component, in the cases where multiple components rely on the same data. In addition to improving efficiency, this often makes it easier to create new components that rely on some part of the existing app state.)

    You can maintain a global app state using e.g. Flux, Redux or Baobab, to name a few options.

    Another advantage of using a global app state, is that you can implement a check (in the app state handler) to ensure you only update the app state with actual changes (i.e. not setting a value if it's the same as it was before).

    Smaller components: Reducing amount of DOM elements to re-render per change

    Another tactic to reduce re-rendering costs is to make your components smaller. Then, each each data change only applies to a little bit of the DOM, because each component has fewer elements to render.

    In my opinion you should always try to do this, as, in addition to the performance aspect, it makes you code more understandable, reusable and maintainable.

    Choosing tactics

    Each of the tactics can be used alone or in conjunction, but applying both tactics from the first group is typically not going to show notable improvements over applying just one of them.

    I'd recommend starting with making your components smaller, because that gives you other advantages as well, as mentioned above.

    0 讨论(0)
提交回复
热议问题