What is the Java equivalent to this preg_replace?

Question

wordword word\";
    $str = preg_replace(\"/word(?!([^<]+)?>)/i\",\"repl\",$str);
    echo $str;         


        

Answer 1

Use the String.replaceAll() method:

class Test {
  public static void main(String[] args) {
    String str = "word <a href=\"word\">word</word>word word";
    str = str.replaceAll("word(?!([^<]+)?>)", "repl");
    System.out.println(str);
  }
}

Hope this helps.

Answer 2

To translate that regex for use in Java, all you have to do is get rid of the / delimiters and change the trailing i to an inline modifier, (?i). But it's not a very good regex; I would use this instead:

(?i)word(?![^<>]++>)

According to RegexBuddy's Debug feature, when it tries to match the word in <a href="word">, the original regex requires 23 steps to reject it, while this one takes only seven steps. The actual Java code is

str = str.replaceAll("(?i)word(?![^<>]++>)", "repl");

Answer 3

Before providing a further answer, are you trying to parse an html document? If so, don't use regexes, use an html parser.