reverse the position of integer digits?

Question

i have to reverse the position of integer like this

input = 12345

output = 54321

i made this but it gives wrong output e.g 5432

#include         


        

Answer 1

The following code works for a two-digit number only.

#include<iostream>
using namespace std;

int main() {
    int n;
    cin >> n;
    cout << (n%10) << (n/10);    
return 0;
}

Answer 2

If I were doing it, I'd (probably) start by creating the new value as an int, and then print out that value. I think this should simplify the code a bit. As pseudocode, it'd look something like:

output = 0;

while (input !=0)
    output *= 10
    output += input % 10
    input /= 10
}
print output

The other obvious possibility would be to convert to a string first, then print the string out in reverse:

std::stringstream buffer;

buffer << input;

cout << std::string(buffer.str().rbegin(), buffer.str().rend());

Answer 3

Your loop terminates too early. Change

}while(num/i!=0);

to

}while((num*10)/i!=0);

to get one more iteration, and your code will work.

Answer 4

replace your while statement

with

while (i<10*num)

Answer 5

int a,b,c,d=0;
cout<<"plz enter the number"<<endl;
cin>>a;
b=a;
do
{
    c=a%10;
    d=(d*10)+c; 
    a=a/10;
}
while(a!=0);
cout<<"The reverse of the number"<<d<<endl;
if(b==d)
{
    cout<<"The entered number is palindom"<<endl;
}
else
{
    cout<<"The entered number is not palindom"<<endl;
}

}

Answer 6

public class TestDS {

public static void main(String[] args) {

    System.out.println(recursiveReverse(234));
           System.out.println(recursiveReverse(234 ,0));



}



public static int reverse(int number){

    int reversedNumber = 0;
    int temp = 0;


    while(number > 0){

        //use modulus operator to strip off the last digit
        temp = number%10;

        //create the reversed number
        reversedNumber = reversedNumber * 10 + temp;
        number = number/10;

    }



    return reversedNumber;

}



private static int reversenumber =0;
public static int recursiveReverse(int number){

    if(number <= 0){

        return reversenumber;
    }

    reversenumber = reversenumber*10+(number%10);
    number =number/10;

    return recursiveReverse(number);

}

public static int recursiveReverse(int number , int reversenumber){

    if(number <= 0){

        return reversenumber;
    }

    reversenumber = reversenumber*10+(number%10);
    number =number/10;

    return recursiveReverse(number,reversenumber);

}

}