This method is part of a module; And despite the error...
Uncaught TypeError: Cannot read property \'1\' of null(…)
works to a small degree, howeve
String#match returns either null
(no match) or an array with the matches.
var domain = link.href.match(/(https?:\/\/.+?)\//)[1];
// ^^^^^
Workaround with check
var domain = link.href.match(/(https?:\/\/.+?)\//);
if (domain) {
// do something with domain[1]
}
Per string.match():
Return value
An Array containing the entire match result and any parentheses-captured matched results; null if there were no matches.
The regular expression should match the string, as well as the protocol and domain like you have it (i.e. the grouping surrounded by parentheses (https?:\/\/.+?)
). You can ensure that the return value is not null (so it should be an array) and that is has more that one element before attempting to access index 1 (since the 1st index should be 0) like this:
var matches = link.href.match(/(https?:\/\/.+?)\//);
if (matches !== null && matches.length > 1) {
So take a look at this example:
function match(link) {
var matches=link.href.match(/(https?:\/\/.+?)\//);
if (matches !== null && matches.length > 1) {
var protocolAndDomain = matches[1];
console.log('protocol and domain: ',protocolAndDomain );
}
else {
console.log('no matching protocol and domain');
}
}
var link = { href: 'stackoverflow.com'};
match(link); //should find no matches
var link2 = { href: 'https://domain.com/'};
match(link2); //should match https://domain.com
I use the term protocol and domain because the expression is looking for the protocol (i.e. https://) before the domain. For more information about the parts of the URL, refer to this MDN page.
You can use an if statement to check if the match is null like the other answers have mentioned.
Or you can use the logical or operator to get it onto one line and make it cleaner e.g.
var domain = (link.href.match(/(https?:\/\/.+?)\//) || [])[1];
You get a Type error because when the match is false the function returns null
and you cannot access index 1 of null
as it is not an array.
null[1]
causes a type error
By using the logical OR operator ||
the domain variable is set to second condition when the first condition is falsey.
So when the match is false the result defaults to an empty array []
and you can access any index of an empty array without getting an error and it results in undefined
This will make domain = undefined
when the match is false.
I really wish type errors weren't a problem in JS especially with objects. I seem to have add a lot of if statement and extra code every other line just to deal with type errors.