JavaScript Split around curly braces

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再見小時候
再見小時候 2021-02-09 09:40

I have a string format inside of a string variable:

\"{0} Hello World {1}\"

I need to split it into something like this:

\"{0}\         


        
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  • 2021-02-09 10:14

    You can use the following:

    \s*({\d+})\s*
    

    JS Code:

    var regex = /\s*({\d+})\s*/g;
    var split_string = "{0} Hello World {1}".split(regex).filter(Boolean);
    alert(split_string);

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  • 2021-02-09 10:18
    var myString = "{0} Hello World {1}"
    var splits = myString.split(/\s?{\d}\s?/);
    

    which would return ["", "Hello World", ""],

    var count = 0;
    for (var i=0; i< splits.length; i++) {
        if (splits[i] === "") {
            splits[i] = "{" + count + "}";
            count++;
        }
    }
    

    now splits would have what you need.

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  • 2021-02-09 10:21

    You can use Split with a regex having capturing group(s):

    If separator is a regular expression that contains capturing parentheses, then each time separator is matched, the results (including any undefined results) of the capturing parentheses are spliced into the output array.

    var re = /\s*(\{[0-9]+\})\s*/g;
    var splt = "{0} Hello World {1}".split(re).filter(Boolean);
    alert(splt);

    Regex explanation:

    • \s* - Any number of whitespaces
    • (\{[0-9]+\}) - A capturing group that matches:
      • \{ - a literal {
      • [0-9]+ - 1 or more digits
      • \} - a literal }
    • \s* - Any number of whitespaces

    filter can help get rid of empty elements in the array.

    filter() calls a provided callback function once for each element in an array, and constructs a new array of all the values for which callback returns a true value or a value that coerces to true. callback is invoked only for indexes of the array which have assigned values; it is not invoked for indexes which have been deleted or which have never been assigned values.

    Array elements which do not pass the callback test are simply skipped, and are not included in the new array.

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  • 2021-02-09 10:24

    You can just filter out the empty strings if you want:

    var s = "{0} Hello World {1}";
    s.split(/({\d+})/).filter(Boolean);
    

    which returns

    ["{0}", " Hello World ", "{1}"]
    
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  • 2021-02-09 10:28

    You can do like this:

    var myregexp = /({.*?})(.*?)({.*?})/im;
    var match = myregexp.exec(subject);
       if (match != null) 
       {
         result1 = match[1];
         result2 = match[2];
         result3 = match[3];
       }
    
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