OpenCV KeyPoint: information about angle and octave

前端 未结 5 1026
时光说笑
时光说笑 2021-02-09 08:31

I want to know more about KeyPoints, so can anyone told me what are


KeyPoint::angle

In OpenCV docs was mentioned that angle is computed orientation of the

相关标签:
5条回答
  • 2021-02-09 08:39

    If someone came to this question wondering why does keypoint.octave have such a weird value (e.g. 16253184), it is because it actually carries the information on:

    • the actual octave in the least significant byte of the keypoint.octave field
    • the layer of that octave in the second least significant byte of the keypoint.octave field
    • something else that gets packed into the third least significant byte by the SIFT keypoint detection, but doesn't get used by the SIFT descriptor

    keypoint.octave gets unpacked into the variables octave, layer, and scale (scale is just 1/2^octave) with the method unpackOctave (see OpenCV implementation).

    To get a visual understanding of variables octave and layer, this image might help:

    0 讨论(0)
  • 2021-02-09 08:41

    If you really want to understand the basics, just go to the basics:

    http://www.cs.ubc.ca/~lowe/papers/ijcv04.pdf

    It is the first, and one of the most influential papers about image feature description/extraction. You may find it a bit hard to swallow, but it offers a good explanation of a complex problem.

    0 讨论(0)
  • 2021-02-09 08:52

    If someone doesn't want to read the paper by Lowe, which @sammy mentioned, here is some short resume:

    • Image pyramid (see OpenCV doc and wiki) is basically a set of images based on a single image that we have downsampled and downscaled multiple times. An example for such pyramid is the Gaussian pyramid. We use pyramids in feature detection and matching for various reasons. It has been noticed in the past that downsampling and also downscaling an image to a certain level does not mean that we loose all the features that we require for feature matching for example and in fact it often removes some of the noise. High resolution (not to be confused with the image's width and height!) is also often not something that we need since (wikipedia) higher resolution also means more details in the image but more details also means more processing power required, which is a killer if you run your application on a platform with low performance and low power consumption in mind such as smartphones. If you combine this with a huge scale of your image (dimensions) the whole thing gets even worse. Of course it depends on the image and on the number of layers our pyramid has. As we know downsampling alters the pixels in the image in a way. Each feature is described by a keypoint and a descriptor. Because of the change in pixels when downsampling features also change and so do their descriptors and keypoints. That is why a keypoint has to store the information at which level in the image pyramid it was extracted. Note that creating image pyramids requires a decent amount of resources. However this trade-off is justified when you start doing something else with those images such as matching.
    • Keypoint angle relates to the orientation of the feature that the keypoint represents. A keypoint is actually not a single pixel but a small region inside a feature (calling .pt.x and .pt.y just returns the center of the keypoint) so when changing it's orientation the pixels change their position from the perspective of the keypoint. Imagine you have a house with a door, roof etc. We extract some features of that house. Then we turn our camera upside down and take a new photo from the exact same position. If the feature extractor supports orientation, we should get (almost) the same features (ergo same keypoints) as in the picture we shot before that change in the orientation of our camera. If the feature extractor does not support orientation, we might loose most of our previously detected features and/or get new ones.

    I recommend reading "Learning OpenCV". It is outdated in terms of OpenCV's API but the theory discussed there is really well explained.

    0 讨论(0)
  • 2021-02-09 08:58

    Even though I know conceptual about the angle and octave, I wonder what the float angle mean, so I look in the source code of OpenCV2.3.1
    in sift.cpp

    inline KeyPoint featureToKeyPoint( const feature& feat )
    {
        float size = (float)(feat.scl * SIFT::DescriptorParams::GET_DEFAULT_MAGNIFICATION() * 4); // 4==NBP
        float angle = (float)(feat.ori * a_180divPI);
        return KeyPoint( (float)feat.x, (float)feat.y, size, angle, feat.response, feat.feature_data->octv, feat.class_id );
    }
    

    ok, I get the angle definition, but what is feat.ori and a_180divPI
    the latter is easy to find

    const double a_180divPI = 180./CV_PI;
    

    the former needs some effort, after look through several methods, I get

    struct feature
    {
        double x;                      /**< x coord */
        double y;                      /**< y coord */
    
        double scl;                    /**< scale of a Lowe-style feature */
        double ori;                    /**< orientation of a Lowe-style feature */
    
        ...
    };
    

    and the feat.ori is computed through several steps according to Lowe's Paper ( http://www.cs.ubc.ca/~lowe/papers/ijcv04.pdf ), including calculate ori_hist, smooth the histogram and add_good_ori_feature.
    I am not 100% sure about the exactly meaning of the ori, but I strongly doubt that OpenCV have turned the ori to an proper arc representation, and the final result angle is the normal meaning angel range from -180 degree to 180 degree. The evidences are

    1) ori = arctan2( dy, dx)
    2) bin = cvRound( n * ( ori * CV_PI ) / PI_2 )
    3) new_feat->ori = ( ( PI2 * bin ) / n ) - CV_PI; 
    

    hope help you

    0 讨论(0)
  • 2021-02-09 09:04

    This may help with regards to the octave:

    http://en.wikipedia.org/wiki/Gaussian_pyramid

    Basically, the image is blurred to varying degrees. The degree at which the feature is found is the 'octave' level of that feature.

    0 讨论(0)
提交回复
热议问题