Get Python function's owning class from decorator

Question

I have a decorator in PY. It is a method and takes the function as a parameter. I want to create a directory structure based based on the passed function. I am using the modu

Answer 1

If fn is an instancemethod, then you can use fn.im_class.

>>> class Foo(object):
...     def bar(self):
...         pass
...
>>> Foo.bar.im_class
__main__.Foo

Note that this will not work from a decorator, because a function is only transformed into an instance method after the class is defined (ie, if @specialTest was used to decorate bar, it would not work; if it's even possible, doing it at that point would have to be done by inspecting the call stack or something equally unhappy).

Answer 2

In Python 2 you can use im_class attribute on the method object. In Python 3, it'll be __self__.__class__ (or type(method.__self__)).