Omit rows containing specific column of NA

Question

I want to know how to omit NA values in a data frame, but only in some columns I am interested in.

For example,

DF <- data.frame(x =          


        

Answer 1

Just try this:

DF %>% t %>% na.omit %>% t

It transposes the data frame and omits null rows which were 'columns' before transposition and then you transpose it back.

Answer 2

You could use the complete.cases function and put it into a function thusly:

DF <- data.frame(x = c(1, 2, 3), y = c(0, 10, NA), z=c(NA, 33, 22))

completeFun <- function(data, desiredCols) {
  completeVec <- complete.cases(data[, desiredCols])
  return(data[completeVec, ])
}

completeFun(DF, "y")
#   x  y  z
# 1 1  0 NA
# 2 2 10 33

completeFun(DF, c("y", "z"))
#   x  y  z
# 2 2 10 33

EDIT: Only return rows with no NAs

If you want to eliminate all rows with at least one NA in any column, just use the complete.cases function straight up:

DF[complete.cases(DF), ]
#   x  y  z
# 2 2 10 33

Or if completeFun is already ingrained in your workflow ;)

completeFun(DF, names(DF))

Answer 3

Hadley's tidyr just got this amazing function drop_na

library(tidyr)
DF %>% drop_na(y)
  x  y  z
1 1  0 NA
2 2 10 33

Answer 4

Omit row if either of two specific columns contain <NA>.

DF[!is.na(DF$x)&!is.na(DF$z),]

Answer 5

It is possible to use na.omit for data.table:

na.omit(data, cols = c("x", "z"))

Answer 6

Try this:

cc=is.na(DF$y)
m=which(cc==c("TRUE"))
DF=DF[-m,]