How to use XGboost in PySpark Pipeline

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面向向阳花
面向向阳花 2021-02-09 04:23

I want to update my code of pyspark. In the pyspark, it must put the base model in a pipeline, the office demo of pipeline use the LogistictRegression as an base model. However,

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  • 2021-02-09 04:57

    There is an XBoost Implementation for Spark 2.4 and over here:

    https://xgboost.readthedocs.io

    Note that this is an external library but it should work easily with spark.

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  • 2021-02-09 05:09

    There is no XGBoost classifier in Apache Spark ML (as of version 2.3). Available models are listed here : https://spark.apache.org/docs/2.3.0/ml-classification-regression.html

    If you want to use XGBoost you should do it without pyspark (convert your spark dataframe to a pandas dataframe with .toPandas()) or use another algorithm (https://spark.apache.org/docs/2.3.0/api/python/pyspark.ml.html#module-pyspark.ml.classification).

    But if you really want to use XGBoost with pyspark, you'll have to dive into pyspark to implement a distributed XGBoost yourself. Here is an article where they do so : http://dmlc.ml/2016/10/26/a-full-integration-of-xgboost-and-spark.html

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  • 2021-02-09 05:15

    There is a maintained (used in production by several companies) distributed XGBoost library as mentioned above (https://github.com/dmlc/xgboost), however to use it from PySpark is a bit tricky, someone made a working pyspark wrapper for version 0.72 of the library, with 0.8 support in progress.

    See here https://medium.com/@bogdan.cojocar/pyspark-and-xgboost-integration-tested-on-the-kaggle-titanic-dataset-4e75a568bdb, and https://github.com/dmlc/xgboost/issues/1698 for the full discussion.

    Make sure the xgboost jars are in your pyspark jar path.

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