Get person's age in Ruby

Question

I\'d like to get a person\'s age from its birthday. now - birthday / 365 doesn\'t work, because some years have 366 days. I came up with the following code:

Answer 1

I think it's alot better to do not count months, because you can get exact day of a year by using Time.zone.now.yday.

def age
  years  = Time.zone.now.year - birthday.year
  y_days = Time.zone.now.yday - birthday.yday

  y_days < 0 ? years - 1 : years
end

Answer 2

I believe this is functionally equivalent to @philnash's answer, but IMO more easily understandable.

class BirthDate
  def initialize(birth_date)
    @birth_date = birth_date
    @now = Time.now.utc.to_date
  end

  def time_ago_in_years
    if today_is_before_birthday_in_same_year?
      age_based_on_years - 1
    else
      age_based_on_years
    end
  end

  private

  def age_based_on_years
    @now.year - @birth_date.year
  end

  def today_is_before_birthday_in_same_year?
    (@now.month < @birth_date.month) || ((@now.month == @birth_date.month) && (@now.day < @birth_date.day))
  end
end

Usage:

> BirthDate.new(Date.parse('1988-02-29')).time_ago_in_years
 => 31 

Answer 3

Came up with a Rails variation of this solution

def age(dob)
    now = Date.today
    age = now.year - dob.year
    age -= 1 if dob > now.years_ago(age)
    age
end

Answer 4

I've found this solution to work well and be readable for other people:

    age = Date.today.year - birthday.year
    age -= 1 if Date.today < birthday + age.years #for days before birthday

Easy and you don't need to worry about handling leap year and such.

Answer 5

My suggestion:

def age(birthday)
    ((Time.now - birthday.to_time)/(60*60*24*365)).floor
end

The trick is that the minus operation with Time returns seconds

Answer 6

This answer is the best, upvote it instead.

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I like @philnash's solution, but the conditional could be compacter. What that boolean expression does is comparing [month, day] pairs using lexicographic order, so one could just use ruby's string comparison instead:

def age(dob)
  now = Date.today
  now.year - dob.year - (now.strftime('%m%d') < dob.strftime('%m%d') ? 1 : 0)
end