I\'m trying to develop a deeper understanding of using the dot (".") with dplyr
and using the .data
pronoun with dplyr
. The code
The .
variable comes from magrittr
, and is related to pipes. It means "the value being piped into this expression". Normally with pipes, the value from a previous expression becomes argument 1 in the next expression, but this gives you a way to use it in some other argument.
The .data
object is special to dplyr
(though it is implemented in the rlang
package). It does not have any useful value itself, but when evaluated in the dplyr
"tidy eval" framework, it acts in many ways as though it is the value of the dataframe/tibble. You use it when there's ambiguity: if you have a variable with the same name foo
as a dataframe column, then .data$foo
says it is the column you want (and will give an error if it's not found, unlike data$foo
which will give NULL
). You could alternatively use .env$foo
, to say to ignore the column and take the variable from the calling environment.
Both .data
and .env
are specific to dplyr
functions and others using the same special evaluation scheme, whereas .
is a regular variable and can be used in any function.
Edited to add: You asked why names(.data)
didn't work. If @r2evans excellent answer isn't enough, here's a different take on it: I suspect the issue is that names()
isn't a dplyr
function, even though names.rlang_fake_data_pronoun
is a method in rlang
. So the expression names(.data)
is evaluated using regular evaluation instead of tidy evaluation. The method has no idea what dataframe to look in, because in that context there isn't one.
Up front, I think .data
's intent is a little confusing until one also considers its sibling pronoun, .env
.
The dot .
is something that magrittr::%>%
sets up and uses; since dplyr
re-exports it, it's there. And whenever you reference it, it is a real object, so names(.)
, nrow(.)
, etc all work as expected. It does reflect data up to this point in the pipeline.
.data
, on the other hand, is defined within rlang
for the purpose of disambiguating symbol resolution. Along with .env
, it allows you to be perfectly clear on where you want a particular symbol resolved (when ambiguity is expected). From ?.data, I think this is a clarifying contrast:
disp <- 10
mtcars %>% mutate(disp = .data$disp * .env$disp)
mtcars %>% mutate(disp = disp * disp)
However, as stated in the help pages, .data
(and .env
) is just a "pronoun" (we have verbs, so now we have pronouns too), so it is just a pointer to explain to the tidy internals where the symbol should be resolved. It's just a hint of sorts.
So your statement
both
.
and.data
just mean "our result up to this point in the pipeline."
is not correct: .
represents the data up to this point, .data
is just a declarative hint to the internals.
Consider another way of thinking about .data
: let's say we have two functions that completely disambiguate the environment a symbol is referenced against:
get_internally
, this symbol must always reference a column name, it will not reach out to the enclosing environment if the column does not exist; andget_externally
, this symbol must always reference a variable/object in the enclosing environment, it will never match a column.In that case, translating the above examples, one might use
disp <- 10
mtcars %>%
mutate(disp = get_internally(disp) * get_externally(disp))
In that case, it seems more obvious that get_internally
is not a frame, so you can't call names(get_internally)
and expect it to do something meaningful (other than NULL
). It'd be like names(mutate)
.
So don't think of .data
as an object, think of it as a mechanism to disambiguate the environment of the symbol. I think the $
it uses is both terse/easy-to-use and absolutely-misleading: it is not a list
-like or environment
-like object, even if it is being treated as such.
BTW: one can write any S3 method for $
that makes any classed-object look like a frame/environment:
`$.quux` <- function(x, nm) paste0("hello, ", nm, "!")
obj <- structure(0, class = "quux")
obj$r2evans
# [1] "hello, r2evans!"
names(obj)
# NULL
(The presence of a $
accessor does not always mean the object is a frame/env.)
On a theoretical level:
.
is the magrittr pronoun. It represents the entire input (often a data frame when used with dplyr) that is piped in with %>%
.
.data
is the tidy eval pronoun. Technically it is not a data frame at all, it is an evaluation environment.
On a practical level:
.
will never be modified by dplyr. It remains constant until the next piped expression is reached. On the other hand, .data
is always up to date. That means you can refer to previously created variables:
mtcars %>%
mutate(
cyl2 = cyl + 1,
am3 = .data[["cyl2"]] + 10
)
And you can also refer to column slices in the case of a grouped data frame:
mtcars %>%
group_by(cyl) %>%
mutate(cyl2 = .data[["cyl"]] + 1)
If you use .[["cyl"]]
instead, the entire data frame will be subsetted and you will get an error because the input size is not the same as the group slice size. Tricky!
Compare mtcars %>% count(.data[["cyl"]])
vs. mtcars %>% count(.[["cyl"]])
.
mtcars %>% count(.[["cyl"]])
.[["cyl"]] n
1 4 11
2 6 7
3 8 14
mtcars %>% count(.data[["cyl"]])
cyl n
1 4 11
2 6 7
3 8 14
.
is literally just the previous result. So the first is similar to:
. <- mtcars
count(., .[["cyl"]])
The second is a shorthand for looking up the variable by the string "cyl" and treating the previous result as the search path for the variable. For example, suppose you mispelled your variable name:
mtcars %>% count(.[["cyll"]])
n
1 32
mtcars %>% count(.data[["cyll"]])
Error: Must group by variables found in `.data`.
* Column `cyll` is not found.
Using .
will not throw an error because indexing to a non-existing column is a valid base-R operation that returns NULL
.
Using .data
will throw because using a non-existent variable:
mtcars %>% count(cyll)
Also throws.