how to sort mixed numeric/alphanumeric array in javascript

Question

I have a mixed array that I need to sort by number, alphabet and then by digit-

[\'A1\', \'A10\', \'A11\', \'A12\', \'A3A\', \'A3B\', \'A3\', \'A4\', \'B10\', \'         


        

Answer 1

You could sort it with splitted array by type and check for equality first and then by type.

var array = ['A1', 'A10', 'A11', 'A12', 'A3A', 'A3B', 'A3', 'A4', 'B10', 'B2', 'F1', '1', '2', 'F3'];

array.sort(function (a, b) {
    var isNumber = function (v) { return (+v).toString() === v; },
        aa = a.match(/\d+|\D+/g),
        bb = b.match(/\d+|\D+/g),
        i = 0,
        l = Math.min(aa.length, bb.length);

    while (i < l && aa[i] === bb[i]) {
        i++;
    }
    if (i === l) {
        return aa.length - bb.length;
    }
    if (isNumber(aa[i]) && isNumber(bb[i])) {
        return aa[i] - bb[i];
    }
    return aa[i].localeCompare(bb[i]);
});

console.log(array);

.as-console-wrapper { max-height: 100% !important; top: 0; }

Answer 2

var a=[ {
    "LIST": "14:NATURAL RESOURCES"
},
{
    "LIST": "7:DIVERSITY IN LIVING ORGANISMS"
},
{
    "LIST": "3:ATOMS AND MOLECULES"
},
{
    "LIST": "10:GRAVITATION"
},
{
    "LIST": "6:TISSUES"
}]

var c=a.sort(function(a,b){
let aa=a.LIST,bb=b.LIST;
return parseInt(aa.split(":")[0] - bb.split(":")[0])

})

console.log(c)

Answer 3

Try this functionality. it give the result which you want exactly

   var arr = ['A1', 'A10', 'A11', 'A12', 'A3A', 'A3B', 'A3', 'A4', 'B10', 'B2', 'F1', '1', '2', 'F3'];
function sortFn(a, b) {     
    var ax = [], bx = [];
    a.replace(/(\d+)|(\D+)/g, function(_, $1, $2) { ax.push([$1 || Infinity, $2 || ""]) });
    b.replace(/(\d+)|(\D+)/g, function(_, $1, $2) { bx.push([$1 || Infinity, $2 || ""]) });        
    while(ax.length && bx.length) {
        var an = ax.shift();
        var bn = bx.shift();
        var nn = (an[0] - bn[0]) || an[1].localeCompare(bn[1]);
        if(nn) return nn;
    }
    return ax.length - bx.length;      
}
console.log(arr.sort(sortFn));

Answer 4

var arr = ['A1', 'A10', 'A11', 'A12', 'A3A', 'A3B', 'A3', 'A4', 'B10', 'B2', 'F1', '1', '2', 'F3'];

// regular expression to get the alphabetic and the number parts, if any
var regex = /^([a-z]*)(\d*)/i;

function sortFn(a, b) {
  var _a = a.match(regex);
  var _b = b.match(regex);

  // if the alphabetic part of a is less than that of b => -1
  if (_a[1] < _b[1]) return -1;
  // if the alphabetic part of a is greater than that of b => 1
  if (_a[1] > _b[1]) return 1;

  // if the alphabetic parts are equal, check the number parts
  var _n = parseInt(_a[2]) - parseInt(_b[2]);
  if(_n == 0) // if the number parts are equal start a recursive test on the rest
      return sortFn(a.substr(_a[0].length), b.substr(_b[0].length));
  // else, just sort using the numbers parts
  return _n;
}

console.log(arr.sort(sortFn));

Note: the i modifier in the regular expression (/.../i) means case-insensitive (looks for both lowercases and uppercases).