Python list of first day of month for given period

Question

I am trying find an efficient way of creating a list of dates only including the first day of the month for a given period. Something like this but better:

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Answer 1

This is the same as @Andrew's answer, but much faster:

dates = []
date = datetime.date.today()
while date.year < 2015:
    if date.day == 1:
        dates.append(date)
        # I added the following line:
        date += datetime.timedelta(days=27)
    date += datetime.timedelta(days=1)

Using force, but not being brutal.

Answer 2

>>> startyear = 2014
>>> startmonth = 4
>>> endyear = 2015
>>> endmonth = 2
>>> [datetime.date(m/12, m%12+1, 1) for m in xrange(startyear*12+startmonth-1, endyear*12+endmonth)]
[datetime.date(2014, 4, 1), datetime.date(2014, 5, 1), datetime.date(2014, 6, 1), datetime.date(2014, 7, 1), datetime.date(2014, 8, 1), datetime.date(2014, 9, 1), datetime.date(2014, 10, 1), datetime.date(2014, 11, 1), datetime.date(2014, 12, 1), datetime.date(2015, 1, 1), datetime.date(2015, 2, 1)]

For Python 3, you'll need to use range instead of xrange, and // (floor division) instead of / (which does float division in Python 3):

[datetime.date(m//12, m%12+1, 1) for m in range(startyear*12+startmonth-1, endyear*12+endmonth)]