How do you append an int to a string in C++? [duplicate]

Answer 1

cout << "Player" << i ;

Answer 2

If using Windows/MFC, and need the string for more than immediate output try:

int i = 4;
CString strOutput;
strOutput.Format("Player %d", i);

Answer 3

Well, if you use cout you can just write the integer directly to it, as in

std::cout << text << i;

The C++ way of converting all kinds of objects to strings is through string streams. If you don't have one handy, just create one.

#include <sstream>

std::ostringstream oss;
oss << text << i;
std::cout << oss.str();

Alternatively, you can just convert the integer and append it to the string.

oss << i;
text += oss.str();

Finally, the Boost libraries provide boost::lexical_cast, which wraps around the stringstream conversion with a syntax like the built-in type casts.

#include <boost/lexical_cast.hpp>

text += boost::lexical_cast<std::string>(i);

This also works the other way around, i.e. to parse strings.

Answer 4

These work for general strings (in case you do not want to output to file/console, but store for later use or something).

boost.lexical_cast

MyStr += boost::lexical_cast<std::string>(MyInt);

String streams

//sstream.h
std::stringstream Stream;
Stream.str(MyStr);
Stream << MyInt;
MyStr = Stream.str();

// If you're using a stream (for example, cout), rather than std::string
someStream << MyInt;

Answer 5

The easiest way I could figure this out is the following..
It will work as a single string and string array. I am considering a string array, as it is complicated (little bit same will be followed with string). I create a array of names and append some integer and char with it to show how easy it is to append some int and chars to string, hope it helps. length is just to measure the size of array. If you are familiar with programming then size_t is a unsigned int

#include<iostream>
    #include<string>
    using namespace std;
    int main() {

        string names[] = { "amz","Waq","Mon","Sam","Has","Shak","GBy" }; //simple array
        int length = sizeof(names) / sizeof(names[0]); //give you size of array
        int id;
        string append[7];    //as length is 7 just for sake of storing and printing output 
        for (size_t i = 0; i < length; i++) {
            id = rand() % 20000 + 2;
            append[i] = names[i] + to_string(id);
        }
        for (size_t i = 0; i < length; i++) {
            cout << append[i] << endl;
        }


}

Answer 6

printf("Player %d", i);

(Downvote my answer all you like; I still hate the C++ I/O operators.)

:-P