if I have this interface
public interface someInterface {
// method 1
public String getValue(String arg1);
// method 2
public String getValue(String arg1
An interface serves as a contract for the users of that interface: you specify what methods are available (in all implementations) and how they are called. If two implementations of an interface need a different method, then that method should not be part of the interface:
public interface Lookup {
}
public class MapLookup implements Lookup {
public String getValue(String key) {
//...
}
}
public class GuavaLookup implements Lookup {
public String getValue(String row, String column) {
// ...
}
}
In your program, you will know which implementation you use, so you can simply call the right function:
public class Program {
private Lookup lookup = new MapLookup();
public void printLookup(String key) {
// I hardcoded lookup to be of type MapLookup, so I can cast:
System.out.println(((MapLookup)lookup).getValue(key));
}
}
Alternative approach
If your class Program
is more generic and uses dependency injections, you may not know which implementation you have. Then, I would make a new interface Key
, which can be either type of key:
public interface Lookup {
// ...
public String getValue(Key key);
}
public interface Key {
}
public MapKey implements Key {
private String key;
// ...
}
public GuavaKey implements Key {
private String row, column;
// ...
}
The dependency injection in your program might come from some factory implementation. Since you cannot know which type of lookup you use, you need a single contract for getValue
.
public interface Factory {
public Lookup getLookup();
public Key getKey();
}
public class Program {
private Lookup lookup;
public Program(Factory factory) {
lookup = factory.getLookup();
}
public void printLookup(Factory factory) {
System.out.println((lookup.getValue(factory.getKey()));
}
}
A solution (not very elegant) might look loke this:
public abstract class SomeClass {
public String getValue(String arg1) {
throw new IllegalArgumentException();
}
public String getValue(String arg1, String arg2) {
throw new IllegalArgumentException();
}
}
public class SomeClass1 extends SomeClass {
public String getValue(String arg1) {
// return sth
}
}
public class SomeClass2 extends SomeClass {
public String getValue(String arg1, String arg2) {
// return sth
}
}
However there's a drawback - SomeClass1 and SomeClass2 can't inherit directly other class.
If the second value can be considered optional in a sense and you always have the 2 arguments when calling you could create a wrapper class which implements the 2 parameter interface passing the 1 parameter implementation as a constructor parameter and calling that in the method, e.g. something like this:
interface A{
method1(P1)
}
interface B{
method2(P1, P2)
}
class Wrap implements B{
Wrap(A impl)
override method2(P1, P2){
call impl.method1(P1)
}
}
As of Java 8, you can have an interface provide an implementation of a method, through the use of the default keyword. Therefore a new solution would be to provide a default implementation of both methods which maybe throws an exception, then derive the actual implementation from the default interface.
Anyways here is how you can do this:
public interface SomeInterface {
// method 1
default String getValue(String arg1) {
// you decide what happens with this default implementation
}
// method 2
default String getValue(String arg1, String arg2) {
// you decide what happens with this default implementation
}
}
Finally, make the classes override the correct methods
public class SomeClass1 implements SomeInterface {
@Override
public String getValue(String arg1) {
return arg1;
}
}
public class SomeClass2 implements SomeInterface {
@Override
public String getValue(String arg1, String arg2) {
return arg1 + " " + arg2;
}
}