Bash command to remove leading zeros from all file names

Question

I have a directory with a bunch of files with names like:

001234.jpg
001235.jpg
004729342.jpg

I want to remove the leading zeros from all file

Answer 1

I dont know sed at all but you can get a listing by using find:

find -type f -name *.jpg

so with the other answer it might look like

find . -type f -name *.jpg | sed -e 's:^0*::'

but i dont know if that sed command holds up or not.

Answer 2

Try using sed, e.g.:

sed -e 's:^0*::'

Complete loop:

for f in `ls`; do
   mv $f $(echo $f | sed -e 's:^0*::')
done

Answer 3

for FILE in `ls`; do mv $FILE `echo $FILE | sed -e 's:^0*::'`; done

Answer 4

In Bash, which is likely to be your default login shell, no external commands are necessary.

shopt -s extglob
for i in 0*[^0]; do mv "$i" "${i##*(0)}"; done

Answer 5

Maybe not the most elegant but it will work.

for i in 0*
do
mv "${i}" "`expr "${i}" : '0*\(.*\)'`"
done

Answer 6

sed by itself is the wrong tool for this: you need to use some shell scripting as well.

Check Rename multiple files with Linux page for some ideas. One of the ideas suggested is to use the rename perl script:

rename 's/^0*//' *.jpg