asp.net mvc - pass partial data model to partial view

Question

I wish to build a partial view that gets a model column and print it. Something like that:

At the view:

@model IEnumerable

        

Answer 1

Start by refactoring and putting the right logic into the right place. This LINQ query has strictly nothing to do in a view. A view is not supposed to do any LINQ queries or whatever to pull data. A view is supposed to work with data that it is passed to it from the controller action under the form of a view model. A controller action builds and passes an adapted view model that you define for the view.

So as always you start by defining a view model that will be adapted to the requirements of your view:

public class MyViewModel
{
    public IEnumerable<Brand> Brands { get; set; } 
}

then you write a controller action that will populate this view model and pass it to the view:

public ActionResult Foo()
{
    IEnumerable<products_comparison.Models.Product> products = ...
    var model = new MyViewModel
    {
        Brands = (from r in Model select r.Brand).Distinct()
    };
    return View(model);
}

then a view:

@model MyViewModel
<table>
    <tr>
        <th>
            Brand
        </th>
    </tr>
    @Html.DisplayFor(x => x.Brands)
</table>

and finally you could define a corresponding display template which will automatically be rendered for each element of the Brands collection of your view model (~/Views/Shared/DisplayTemplates/Brand.cshtml):

@model Brand
<tr>
    <td>
        @Html.DisplayForModel()
    </td>
</tr>

Answer 2

For 1 try changing @Html.RenderPartial("_DisplayAttribute",Brand) to @Html.Partial("_DisplayAttribute",Brand)

You will also need to specify the model in the partial view like @model products_comparison.Models.Brand or something like it

Also please clarify 2 & 3 as they are not clear what you want