Display numbers from 1 to 100 without loops or conditions [closed]

Answer 1

download from pastebin

System.out.println((new URL("http://pastebin.com/pastebin.php?dl=f722c7eb0")).getContent())

Answer 2

In C++:

#include <iostream>

class a {
  static unsigned i;

public:
  a() {
    std::cout << ++i << std::endl;
  }
};

unsigned a::i = 0U;

int main() {
  a array[100];
}

This solution neither uses loops nor recursion for printing numbers from 1 to 100.

Answer 3

Does it have to be Java? If ruby's allowed:

puts [*1..100].join("\n")

I'd like to see anything this concise in Java.

Answer 4

Didn't see this in here, using the termination order of the && operator.

public class count100 {

    public static boolean loop(int i) {
        System.out.println(100-i);
        return i > 0 && loop(i-1);
    }

    public static void main(String[] args) {
        loop(99);
    }
}

Answer 5

Implement a recursive call incrementing and printing the number. Configure your VM to run out of stack after 100 calls. No conditions, no loops. cough ;-)

Answer 6

public class PrintUptoHundredWithoutIf {
    public static void main(String[] args) {
        Thread t = new Thread(task());
        t.setDaemon(true);
        t.start();
        sleep((NUMBERS_TO_PRINT * SLEEP_PERIOD_IN_MILLIS)
                + OS_SLEEP_RESPONSE_IN_MILLIS);
    }

    private static final int SLEEP_PERIOD_IN_MILLIS = 1000;
    private static final int NUMBERS_TO_PRINT = 100;
    private static final int OS_SLEEP_RESPONSE_IN_MILLIS = 110;

    public void printUptoHundred(byte seq) {
        int posVal = Math.abs(~seq);
        System.out.println(posVal);
        sleep(SLEEP_PERIOD_IN_MILLIS);
        printUptoHundred((byte) posVal);
    }

    private static Runnable task() {
        return new Runnable() {
            @Override
            public void run() {
                new PrintUptoHundredWithoutIf().printUptoHundred((byte) 0);
            }
        };
    }

    private static void sleep(int millis) {
        try {
            Thread.sleep(millis);
        } catch (Exception e) {
            e.printStackTrace();
        }
    }
}