How to convert tuple to a multi nested dictionary in python?

前端 未结 2 1119
离开以前
离开以前 2021-02-08 21:27

I have a tuple in the following format:

(639283, 298290710, 1385)
(639283, 298290712, 1389)
(639283, 298290715, 1395)
(745310, 470212995, 2061)
(745310, 47021382         


        
相关标签:
2条回答
  • 2021-02-08 21:54

    You can use itertools.groupby to group the tuples based on the first item, and then iterate over those groups in a dict-comprehension to get the desired result.

    >>> from operator import itemgetter
    >>> from pprint import pprint
    >>> from itertools import groupby
    >>> d = {k: dict(x[1:] for x in g) for k, g in groupby(data, key=itemgetter(0))}
    >>> pprint(d)
    {639283: {298290710: 1385, 298290712: 1389, 298290715: 1395},
     745310: {470212995: 2061,
              470213821: 3713,
              470215360: 6791,
              470215361: 6793,
              470215363: 6797},
     911045: {374330803: 4905,
              374330804: 4907,
              374330807: 4913,
              374330808: 4915,
              374330809: 4917}}
    

    Where data is your list of tuples or tuple of tuples.

    0 讨论(0)
  • 2021-02-08 22:03

    You can use tuple unpacking combined with collections.defaultdict to make your life easier.

    Create an outer defaultdict with dict as its default value. Then, you can simply loop through your list of tuples once, setting the values appropriately as you go.

    from collections import defaultdict
    
    d = defaultdict(dict) # dict where the default values are dicts.
    for a, b, c in list_of_tuples: # Each tuple is "key1, key2, value"
        d[a][b] = c
    

    Of course, you presumably know more about what these values actually represent, so you can give your dictionary, and the individual items, better, more descriptive names than a, b, c, and d.

    0 讨论(0)
提交回复
热议问题