Would this be the best way to sort a hash and return Hash object (instead of Array):
h = {\"a\"=>1, \"c\"=>3, \"b\"=>2, \"d\"=>4}
# => {\"a\"=
No, it is not (Ruby 1.9.x)
require 'benchmark'
h = {"a"=>1, "c"=>3, "b"=>2, "d"=>4}
many = 100_000
Benchmark.bm do |b|
GC.start
b.report("hash sort") do
many.times do
Hash[h.sort]
end
end
GC.start
b.report("keys sort") do
many.times do
nh = {}
h.keys.sort.each do |k|
nh[k] = h[k]
end
end
end
end
user system total real
hash sort 0.400000 0.000000 0.400000 ( 0.405588)
keys sort 0.250000 0.010000 0.260000 ( 0.260303)
For big hashes difference will grow up to 10x and more
Note: Ruby >= 1.9.2 has an order-preserving hash: the order keys are inserted will be the order they are enumerated. The below applies to older versions or to backward-compatible code.
There is no concept of a sorted hash. So no, what you're doing isn't right.
If you want it sorted for display, return a string:
"{" + h.sort.map{|k,v| "#{k.inspect}=>#{v.inspect}"}.join(", ") + "}"
or, if you want the keys in order:
h.keys.sort
or, if you want to access the elements in order:
h.sort.map do |key,value|
# keys will arrive in order to this block, with their associated value.
end
but in summary, it makes no sense to talk about a sorted hash. From the docs, "The order in which you traverse a hash by either key or value may seem arbitrary, and will generally not be in the insertion order." So inserting keys in a specific order into the hash won't help.
In Ruby 2.1 it is simple:
h.sort.to_h
I had the same problem ( I had to sort my equipments by their name ) and i solved like this:
<% @equipments.sort.each do |name, quantity| %>
...
<% end %>
@equipments is a hash that I build on my model and return on my controller. If you call .sort it will sort the hash based on it's key value.