PHP var_export with double quotes

后端 未结 0 1716
余生分开走
余生分开走 2021-02-08 19:40

I have an array:

$a = array(
    "filterText" => "Search...",
    "filterNothingFoundMsg" => "NOTHING FOUND!",
);


        
相关标签:
回答
  • 消灭零回复
提交回复
热议问题