Setting active profile and config location from command line in spring boot

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借酒劲吻你
借酒劲吻你 2020-11-27 09:33

I have a spring boot application.

I have three profiles in my application-> development, staging and production. So I have 3 files

  1. ap
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  • 2020-11-27 10:21

    When setting the profile via the Maven plugin you must do it via run.jvmArguments

    mvn spring-boot:run -Drun.jvmArguments="-Dspring.profiles.active=production"
    

    With debug option:

    mvn spring-boot:run -Drun.jvmArguments="-Xdebug -Xrunjdwp:transport=dt_socket,server=y,suspend=n,address=5005 -Dspring.profiles.active=jpa"
    

    I've seen this trip a lot of people up..hope it helps

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  • 2020-11-27 10:21

    Michael Yin's answer is correct but a better explanation seems to be required!

    A lot of you mentioned that -D is the correct way to specify JVM parameters and you are absolutely right. But Michael is also right as mentioned in Spring Boot Profiles documentation.

    What is not clear in the documentation, is what kind of parameter it is: --spring.profiles.active is a not a standard JVM parameter so if you want to use it in your IDE fill the correct fields (i.e. program arguments)

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  • 2020-11-27 10:29

    My best practice is to define this as a VM "-D" argument. Please note the differences between spring boot 1.x and 2.x.

    The profiles to enable can be specified on the command line:

    Spring-Boot 2.x (works only with maven)

    -Dspring-boot.run.profiles=local
    

    Spring-Boot 1.x

    -Dspring.profiles.active=local
    

    example usage with maven:

    Spring-Boot 2.x

    mvn spring-boot:run -Dspring-boot.run.profiles=local
    

    Spring-Boot 1.x and 2.x

    mvn spring-boot:run -Dspring.profiles.active=local
    

    Make sure to separate them with a comma for multiple profiles:

    mvn spring-boot:run -Dspring.profiles.active=local,foo,bar
    
    mvn spring-boot:run -Dspring-boot.run.profiles=local,foo,bar
    
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  • 2020-11-27 10:32

    There's another way by setting the OS variable, SPRING_PROFILES_ACTIVE.

    for eg :

    SPRING_PROFILES_ACTIVE=dev gradle clean bootRun
    

    Reference : How to set active Spring profiles

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  • 2020-11-27 10:32

    We want to automatically pick property file based upon mentioned the profile name in spring.profiles.active and the path in -Dspring.config.location

    application-dev.properties
    

    If we are running jar in Unix OS then we have to use / at the end of -Dspring.config.location otherwise it will give below error.

    Error :: java.lang.IllegalStateException: File extension of config file location 'file:/home/xyz/projectName/cfg' is not known to any PropertySourceLoader. If the location is meant to reference a directory, it must end in '/'

    Example

    java -Dspring.profiles.active=dev -Dspring.config.location=/home/xyz/projectName/cfg/ -jar /home/xyz/project/abc.jar
    

    or

    java -jar /home/xyz/project/abc.jar --spring.profiles.active=dev --spring.config.location=/home/xyz/projectName/cfg/
    
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