Redis - Lua tables as return values - why is this not working

后端 未结 2 1582
悲&欢浪女
悲&欢浪女 2021-02-08 15:47

When I run this code through redis EVAL it return no results. Any idea why this is not working?

redis-cli EVAL \"$(cat bug.lua)\" 0

bug.lua

相关标签:
2条回答
  • 2021-02-08 16:16

    If you refer to the Redis EVAL documentation you can see what are the rules Redis uses to convert a Lua table into a Redis reply:

    1. Lua table (array) -> Redis multi bulk reply (truncated to the first nil inside the Lua array if any)
    2. Lua table with a single ok field -> Redis status reply
    3. Lua table with a single err field -> Redis error reply

    So except with special cases 2 and 3, Redis assumes your table is a sequence (i.e list) which means it reads retv[1], retv[2], ... until it encounters a nil element (here is the corresponding source code section).

    This explains why retv["test"] is ignored in your case.

    If you change your code with:

    local retv = {"This", "is", "a", "bug" }
    retv[5] = 1000
    return retv
    

    Then this additional element gets returned:

    1) "This"
    2) "is"
    3) "a"
    4) "bug"
    5) (integer) 1000
    
    0 讨论(0)
  • 2021-02-08 16:20

    Answer from @deltheil is valid.

    Remember though that you can use cjson library to pack tables and pass them to consumers.

    Your lua file:

    local retv = {"This", "is", "a", "bug" }
    retv["test"] = 1000
    
    return cjson.encode(retv)
    

    Command:

    redis-cli EVAL "$(cat bug.lua)" 0
    

    Result:

    "{\"1\":\"This\",\"2\":\"is\",\"3\":\"a\",\"4\":\"bug\",\"test\":1000}"
    
    0 讨论(0)
提交回复
热议问题