How to match “any character” in regular expression?

Question

The following should be matched:

AAA123
ABCDEFGH123
XXXX123

can I do: \".*123\" ?

Answer 1

.* and .+ are for any chars except for new lines.

Double Escaping

Just in case, you would wanted to include new lines, the following expressions might also work for those languages that double escaping is required such as Java or C++:

[\\s\\S]*
[\\d\\D]*
[\\w\\W]*

for zero or more times, or

[\\s\\S]+
[\\d\\D]+
[\\w\\W]+

for one or more times.

Single Escaping:

Double escaping is not required for some languages such as, C#, PHP, Ruby, PERL, Python, JavaScript:

[\s\S]*
[\d\D]*
[\w\W]*
[\s\S]+
[\d\D]+
[\w\W]+

Test

import java.util.regex.Matcher;
import java.util.regex.Pattern;


public class RegularExpression{

    public static void main(String[] args){

        final String regex_1 = "[\\s\\S]*";
        final String regex_2 = "[\\d\\D]*";
        final String regex_3 = "[\\w\\W]*";
        final String string = "AAA123\n\t"
             + "ABCDEFGH123\n\t"
             + "XXXX123\n\t";

        final Pattern pattern_1 = Pattern.compile(regex_1);
        final Pattern pattern_2 = Pattern.compile(regex_2);
        final Pattern pattern_3 = Pattern.compile(regex_3);

        final Matcher matcher_1 = pattern_1.matcher(string);
        final Matcher matcher_2 = pattern_2.matcher(string);
        final Matcher matcher_3 = pattern_3.matcher(string);

        if (matcher_1.find()) {
            System.out.println("Full Match for Expression 1: " + matcher_1.group(0));
        }

        if (matcher_2.find()) {
            System.out.println("Full Match for Expression 2: " + matcher_2.group(0));
        }
        if (matcher_3.find()) {
            System.out.println("Full Match for Expression 3: " + matcher_3.group(0));
        }
    }
}

Output

Full Match for Expression 1: AAA123
    ABCDEFGH123
    XXXX123

Full Match for Expression 2: AAA123
    ABCDEFGH123
    XXXX123

Full Match for Expression 3: AAA123
    ABCDEFGH123
    XXXX123

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If you wish to explore the expression, it's been explained on the top right panel of regex101.com. If you'd like, you can also watch in this link, how it would match against some sample inputs.

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RegEx Circuit

jex.im visualizes regular expressions:

Answer 2

Try the regex .{3,}. This will match all characters except a new line.

Answer 3

Use the pattern . to match any character once, .* to match any character zero or more times, .+ to match any character one or more times.

Answer 4

I work this Not always dot is means any char. Exception when single line mode. \p{all} should be

String value = "|°¬<>!\"#$%&/()=?'\\¡¿/*-+_@[]^^{}";
String expression = "[a-zA-Z0-9\\p{all}]{0,50}";
if(value.matches(expression)){
    System.out.println("true");
} else {
    System.out.println("false");
}

Answer 5

Yes, you can. That should work.

• . = any char except newline
• \. = the actual dot character
• .? = .{0,1} = match any char except newline zero or one times
• .* = .{0,} = match any char except newline zero or more times
• .+ = .{1,} = match any char except newline one or more times

Answer 6

There are lots of sophisticated regex testing and development tools, but if you just want a simple test harness in Java, here's one for you to play with:

    String[] tests = {
        "AAA123",
        "ABCDEFGH123",
        "XXXX123",
        "XYZ123ABC",
        "123123",
        "X123",
        "123",
    };
    for (String test : tests) {
        System.out.println(test + " " +test.matches(".+123"));
    }

Now you can easily add new testcases and try new patterns. Have fun exploring regex.

See also

• regular-expressions.info/Tutorial