Java regex to strip out XML tags, but not tag contents
I have the following Java code:
str = str.replaceAll(\"<.*?>.*?|<.*?/>\", \"\");
This turns a String like so:
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You can try this too:
str = str.replaceAll("<.*?>", "");Please have a look at the below example for better understanding:
public class StringUtils { public static void main(String[] args) { System.out.println(StringUtils.replaceAll("How now <fizz>brown</fizz> cow.")); System.out.println(StringUtils.replaceAll("How <buzz>now <fizz>brown</fizz><yoda/></buzz> cow.")); } public static String replaceAll(String strInput) { return strInput.replaceAll("<.*?>", ""); } }Output:
How now brown cow. How now brown cow.讨论(0) -
You were almost there ;)
Try this:
str = str.replaceAll("<.*?>", "")讨论(0) -
While there are other correct answers, none give any explanation.
The reason your regex
<.*?>.*?</.*?>|<.*?/>doesn't work is because it will select any tags as well as everything inside them. You can see that in action on debuggex.The reason your second attempt
<.*?></.*?>|<.*?/>doesn't work is because it will select from the beginning of a tag up to the first close tag following a tag. That is kind of a mouthful, but you can understand better what's going on in this example.The regex you need is much simpler:
<.*?>. It simply selects every tag, ignoring if it's open/close. Visualization.讨论(0) -
"How now <fizz>brown</fizz> cow.".replaceAll("<[^>]+>", "")讨论(0) -
This isn't elegant, but it is easy to follow. The below code removes the start and end XML tags if they are present in a line together
<url>"www.xml.com"<\url> , <body>"This is xml"<\body>Regex :
to_replace='<\w*>|<\/\w*>',value=""讨论(0) -
If you want to parse XML log file so you can do with regex {java},
<[^<]+<.so you get<name>DEV</name>. Output like name>DEV. You have to just play with REGEX.讨论(0)
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