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Flask: How to handle application/octet-stream

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甜味超标
甜味超标 2021-02-08 13:06

I want to make a multiple file-upload form.I use jQuery File Uploader. My server-side code:

@app.route(\"/new/photogallery\",methods=[\"POST\"])
def newPhotoGall
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  • 萌比男神i
    2021-02-08 13:26

    I was unable to get a request working using application/octet-stream type posts, but have used multipart/form-data type forms in the past to upload images using flask.

    I have extended what I have done in the past to support multiple upload files and this has worked leveraging werkzeug's FileStorage objects.

    The key here is setting up a post based route that is looking for a request element from a form. This should allow you to POST to the route either via a standard form or an AJAX call.

    Below is a simplified example that is using a form:

    Template for the view:

    <!DOCTYPE HTML>
<html>
<head>
<meta charset="utf-8">
<title>jQuery File Upload Example</title>
</head>
<body>
{% if err %}
    <h4>{{ err }}</h4>
{% endif %}

<form action="/" method=POST enctype=multipart/form-data id="fileupload">
    <input type="file" name="files" data-url="/" multiple>
    <input type=submit value=Post>
</form>

{% if files %}
{% for file in files %}
<p>Uploaded: <b>{{ file }}</b> </p>
{% endfor %}
{% endif %}
</body> 
</html>

    Flask App

    from flask import Flask, request, render_template
from werkzeug import secure_filename, FileStorage
import os

# Flask functions
app = Flask(__name__) 
app.config.from_object(__name__)
DEBUG = True 
# add this so that flask doesn't swallow error messages
app.config['PROPAGATE_EXCEPTIONS'] = True

@app.route('/', methods=['GET', 'POST'])
def uploader():
    if request.method =='POST' and request.files.getlist('files'):
        up_file_list = []

        # Iterate the through a list of files from the form input field
        for a_file in request.files.getlist('files'):
            if a_file.filename:
                # Validate that what we have been supplied with is infact a file
                if not isinstance(a_file, FileStorage):
                    raise TypeError("storage must be a werkzeug.FileStorage")
                # Sanitise the filename
                a_file_name = secure_filename(a_file.filename)
                # Build target
                a_file_target = os.path.join('/tmp/', a_file_name)
                # Save file 
                a_file.save(a_file_target)
                up_file_list.append(a_file_name)
        # Return template
        if up_file_list:
            return render_template('uploader.html', err=None, files=up_file_list)
        else:
            return render_template('uploader.html', err='No Files Uploaded', files=None)
    else:
        return render_template('uploader.html', err=None, files=None) 


# application execution 
if __name__ == '__main__': 
    app.run()
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  • -上瘾入骨i
    2021-02-08 13:34

    Regardless of the the data encoding, you should be able to get the raw data with request.data. In the case of application/octet-stream, you can just write request.data to a binary file.

    An example handler for various data types:

    from flask import json

@app.route('/messages', methods = ['POST'])
def api_message():

    if request.headers['Content-Type'] == 'text/plain':
        return "Text Message: " + request.data

    elif request.headers['Content-Type'] == 'application/json':
        return "JSON Message: " + json.dumps(request.json)

    elif request.headers['Content-Type'] == 'application/octet-stream':
        with open('/tmp/binary', 'wb') as f:
            f.write(request.data)
            f.close()
        return "Binary message written!"

    else:
        return "415 Unsupported Media Type ;)"

    The typical scenario of handling form data is already documented here.

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