Pythonic way to combine FOR loop and IF statement

Question

I know how to use both for loops and if statements on separate lines, such as:

>>> a = [2,3,4,5,6,7,8,9,0]
... xyz = [0,12,4,6,242,7,9]
... for x in         


        

Answer 1

I personally think this is the prettiest version:

a = [2,3,4,5,6,7,8,9,0]
xyz = [0,12,4,6,242,7,9]
for x in filter(lambda w: w in a, xyz):
  print x

Edit

if you are very keen on avoiding to use lambda you can use partial function application and use the operator module (that provides functions of most operators).

https://docs.python.org/2/library/operator.html#module-operator

from operator import contains
from functools import partial
print(list(filter(partial(contains, a), xyz)))

Answer 2

The following is a simplification/one liner from the accepted answer:

a = [2,3,4,5,6,7,8,9,0]
xyz = [0,12,4,6,242,7,9]

for x in (x for x in xyz if x not in a):
    print(x)

12
242

Notice that the generator was kept inline. This was tested on python2.7 and python3.6 (notice the parens in the print ;) )

Answer 3

a = [2,3,4,5,6,7,8,9,0]
xyz = [0,12,4,6,242,7,9]  
set(a) & set(xyz)  
set([0, 9, 4, 6, 7])

Answer 4

Use intersection or intersection_update

• intersection :

  a = [2,3,4,5,6,7,8,9,0]
  xyz = [0,12,4,6,242,7,9]
  ans = sorted(set(a).intersection(set(xyz)))
  

• intersection_update:

  a = [2,3,4,5,6,7,8,9,0]
  xyz = [0,12,4,6,242,7,9]
  b = set(a)
  b.intersection_update(xyz)
  

  then b is your answer