Encapsulating Action and Func?

Question

I\'m trying to make a design for some sort of IExecutable interface. I will not get into details, but the point is that I have several Actions that need to be executed from a ba

Answer 1

You know that you can ignore the return value of a method right? You don't have to use it.

Answer 2

The following interfaces should do the trick -- it's essentially copying the Nullable pattern

public interface IActionBase
{
       bool HasResult { get; }
       void Execute() { }
       object Result { get; }
}

public interface IActionBase<T> : IActionBase
{
       new T Result { get; }
}

public sealed class ActionWithReturnValue<T> : IActionBase<T>
{
       public ActionWithReturnValue(Func<T> action) {  _action = action; }
       private Func<T> _action;

       public bool HasResult { get; private set; }
       object IActionBase.Result { get { return this.Result; } }
       public T Result { get; private set; }
       public void Execute()
       {
            HasResult = false;
            Result = default(T);
            try 
            { 
                 Result = _action();
                 HasResult = true;
             }
            catch
            {
                HasResult = false;
                Result = default(T);   
            }  
       }

}

public sealed class ActionWithoutReturnValue : IActionBase
{
      public bool HasResult { get { return false; } }
      object IActionBase.Result { get { return null; } }
      public void Execute() { //... }
}

Answer 3

what about something simple:

public class ActionExecuter
{
    private MulticastDelegate del;
    public ActionExecuter(MulticastDelegate del)
    {
        this.del = del;
    }

    public object Execute(params object[] p)
    {
        return del.DynamicInvoke(p);
    }
}

Answer 4

If you want a lightweight solution, then the easiest option would be to write two concrete classes. One will contain a property of type Action and the other a property of type Func<T>:

public class ActionWithResult<T> : ActionBase { 
  public Func<T> Action { get; set; } 
}

public class ActionWithoutResult : ActionBase {
  public Action Action { get; set; }
}

Then you can construct the two types like this:

var a1 = new ActionWithResult<int> { 
  CanExecute = true,
  Action = () => { 
    Console.WriteLine("hello!");
    return 10; 
  }
}

If you don't want to make Action property read/write, then you could pass the action delegate as an argument to the constructor and make the property readonly.

The fact that C# needs two different delegates to represent functions and actions is quite annoying. One workaround that people use is to define a type Unit that represents "no return value" and use it instead of void. Then your type would be just Func<T> and you could use Func<Unit> instead of Action. The Unit type could look like this:

public class Unit {
  public static Unit Value { get { return null; } }
}

To create a Func<Unit> value, you'll write:

Func<Unit> f = () => { /* ... */ return Unit.Value; }