Currently, I have the following code...
file_name = content.split(\'=\')[1].replace(\'\"\', \'\') #file, gotten previously
fileName = \"/\" + self.feed + \"/\" +
First, I'm not 100% confident I understand the question, so let me state my assumption: 1) You want to write to a file in a directory that doesn't exist yet. 2) The path is relative (to the current directory). 3) You don't want to change the current directory.
So, given that: Check out these two functions: os.makedirs and os.path.join. Since you want to specify a relative path (with respect to the current directory) you don't want to add the initial "/".
dir_path = os.path.join(self.feed, self.address) # will return 'feed/address'
os.makedirs(dir_path) # create directory [current_path]/feed/address
output = open(os.path.join(dir_path, file_name), 'wb')
Commands like os.mkdir
don't actually require that you make the folder in your current directory; you can put a relative or absolute path.
os.mkdir('../new_dir')
os.mkdir('/home/you/Desktop/stuff')
I don't know of a way to both recursively create the folders and open the file besides writing such a function yourself - here's approximately the code in-line. os.makedirs
will get you most of the way there; using the same mysterious self object you haven't shown us:
dir = "/" + self.feed + "/" + self.address + "/"
os.makedirs(dir)
output = open(os.path.join(dir, file_name), 'wb')
This will create the file feed/address/file.txt
in the same directory as the current script:
import os
file_name = 'file.txt'
script_dir = os.path.dirname(os.path.abspath(__file__))
dest_dir = os.path.join(script_dir, 'feed', 'address')
try:
os.makedirs(dest_dir)
except OSError:
pass # already exists
path = os.path.join(dest_dir, file_name)
with open(path, 'wb') as stream:
stream.write('foo\n')