Aggregate functions in WHERE clause in SQLite

Question

Simply put, I have a table with, among other things, a column for timestamps. I want to get the row with the most recent (i.e. greatest value) timestamp. Currently I\'m doing th

Answer 1

you can simply do

SELECT *, max(timestamp) FROM table

Edit: As aggregate function can't be used like this so it gives error. I guess what SquareCog had suggested was the best thing to do

SELECT * FROM table WHERE timestamp = (select max(timestamp) from table)

Answer 2

SELECT * from foo where timestamp = (select max(timestamp) from foo)

or, if SQLite insists on treating subselects as sets,

SELECT * from foo where timestamp in (select max(timestamp) from foo)

Answer 3

There are many ways to skin a cat.

If you have an Identity Column that has an auto-increment functionality, a faster query would result if you return the last record by ID, due to the indexing of the column, unless of course you wish to put an index on the timestamp column.

SELECT * FROM TABLE ORDER BY ID DESC LIMIT 1

Answer 4

I think I've answered this question 5 times in the past week now, but I'm too tired to find a link to one of those right now, so here it is again...

SELECT
     *
FROM
     table T1
LEFT OUTER JOIN table T2 ON
     T2.timestamp > T1.timestamp
WHERE
     T2.timestamp IS NULL

You're basically looking for the row where no other row matches that is later than it.

NOTE: As pointed out in the comments, this method will not perform as well in this kind of situation. It will usually work better (for SQL Server at least) in situations where you want the last row for each customer (as an example).