How to get list of subdirectories names [duplicate]

Answer 1

You may use os.walk

for i,j,y in os.walk('.'):
    print(i) 

Answer 2

Just use os.path.isdir on the results returned by os.listdir, as in:

def listdirs(path):
    return [d for d in os.listdir(path) if os.path.isdir(os.path.join(path, d))]

Answer 3

That should work :

my_dirs = [d for d in os.listdir('My_directory') if os.path.isdir(os.path.join('My_directory', d))]

Answer 4

os.walk already splits files and folders up into different lists, and works recursively:

for root,dirs,_ in os.walk('.'):
    for d in dirs:
        print os.path.join(root,d)

Answer 5

I usually check for directories, while assembling a list in one go. Assuming that there is a directory called foo, that I would like to check for sub-directories:

import os
output = [dI for dI in os.listdir('foo') if os.path.isdir(os.path.join('foo',dI))]