Resize an image to a square but keep aspect ratio c++ opencv

Question

Is there a way of resizing images of any shape or size to say [500x500] but have the image\'s aspect ratio be maintained, levaing the empty space be filled with whi

Answer 1

You can create another image of the square size you wish, then put your image in the middle of the square image. Something like this:

#include <opencv2/core/core.hpp>
#include <opencv2/highgui/highgui.hpp>
#include "opencv2/imgproc/imgproc.hpp"

int main(int argc, char *argv[])
{
    // read an image
    cv::Mat image1= cv::imread("/home/hdang/Desktop/colorCode.png");

    //resize it
    cv::Size newSize = cv::Size(image1.cols/2,image1.rows/2);
    cv::resize(image1, image1, newSize, 0, 0, cv::INTER_LINEAR);

    //create the square container
    int dstWidth = 500;
    int dstHeight = 500;
    cv::Mat dst = cv::Mat(dstHeight, dstWidth, CV_8UC3, cv::Scalar(0,0,0));

    //Put the image into the container, roi is the new position
    cv::Rect roi(cv::Rect(0,dst.rows*0.25,image1.cols,image1.rows));
    cv::Mat targetROI = dst(roi);
    image1.copyTo(targetROI);

    //View the result
    cv::namedWindow("OpenCV Window");
    cv::imshow("OpenCV Window", dst);

    // wait key for 5000 ms
    cv::waitKey(5000);

    return 0;
}

Answer 2

Not fully optimized, but you can try this:

EDIT handle target size that is not 500x500 pixels and wrapping it up as a function.

cv::Mat GetSquareImage( const cv::Mat& img, int target_width = 500 )
{
    int width = img.cols,
       height = img.rows;

    cv::Mat square = cv::Mat::zeros( target_width, target_width, img.type() );

    int max_dim = ( width >= height ) ? width : height;
    float scale = ( ( float ) target_width ) / max_dim;
    cv::Rect roi;
    if ( width >= height )
    {
        roi.width = target_width;
        roi.x = 0;
        roi.height = height * scale;
        roi.y = ( target_width - roi.height ) / 2;
    }
    else
    {
        roi.y = 0;
        roi.height = target_width;
        roi.width = width * scale;
        roi.x = ( target_width - roi.width ) / 2;
    }

    cv::resize( img, square( roi ), roi.size() );

    return square;
}

Answer 3

Alireza's answer is good, however I modified the code slightly so that I don't add the vertical borders when the image fits vertically and I don't add horizontal borders when the image fits horizontally (this is closer to the original request):

cv::Mat utilites::resizeKeepAspectRatio(const cv::Mat &input, const cv::Size &dstSize, const cv::Scalar &bgcolor)
{
    cv::Mat output;

    // initially no borders
    int top = 0;
    int down = 0;
    int left = 0;
    int right = 0;
    if( h1 <= dstSize.height) 
    {
        // only vertical borders
        top = (dstSize.height - h1) / 2;
        down = top;
        cv::resize( input, output, cv::Size(dstSize.width, h1));
    } 
    else 
    {
        // only horizontal borders
        left = (dstSize.width - w2) / 2;
        right = left;
        cv::resize( input, output, cv::Size(w2, dstSize.height));
    }

    return output;
}

Answer 4

A general approach:

cv::Mat utilites::resizeKeepAspectRatio(const cv::Mat &input, const cv::Size &dstSize, const cv::Scalar &bgcolor)
{
    cv::Mat output;

    double h1 = dstSize.width * (input.rows/(double)input.cols);
    double w2 = dstSize.height * (input.cols/(double)input.rows);
    if( h1 <= dstSize.height) {
        cv::resize( input, output, cv::Size(dstSize.width, h1));
    } else {
        cv::resize( input, output, cv::Size(w2, dstSize.height));
    }

    int top = (dstSize.height-output.rows) / 2;
    int down = (dstSize.height-output.rows+1) / 2;
    int left = (dstSize.width - output.cols) / 2;
    int right = (dstSize.width - output.cols+1) / 2;

    cv::copyMakeBorder(output, output, top, down, left, right, cv::BORDER_CONSTANT, bgcolor );

    return output;
}