Get the full URL in PHP

Answer 1

function full_path()
{
    $s = &$_SERVER;
    $ssl = (!empty($s['HTTPS']) && $s['HTTPS'] == 'on') ? true:false;
    $sp = strtolower($s['SERVER_PROTOCOL']);
    $protocol = substr($sp, 0, strpos($sp, '/')) . (($ssl) ? 's' : '');
    $port = $s['SERVER_PORT'];
    $port = ((!$ssl && $port=='80') || ($ssl && $port=='443')) ? '' : ':'.$port;
    $host = isset($s['HTTP_X_FORWARDED_HOST']) ? $s['HTTP_X_FORWARDED_HOST'] : (isset($s['HTTP_HOST']) ? $s['HTTP_HOST'] : null);
    $host = isset($host) ? $host : $s['SERVER_NAME'] . $port;
    $uri = $protocol . '://' . $host . $s['REQUEST_URI'];
    $segments = explode('?', $uri, 2);
    $url = $segments[0];
    return $url;
}

Note: I just made an update to Timo Huovinen's code, so you won't get any GET parameters in the URL. This URL is plain and removes things like ?hi=i&am=a&get.

Example:

http://www.example.com/index?get=information

will be shown as:

http://www.example.com/index

This is fine unless you use GET paramaters to define some specific content, in which case you should use his code! :-)

Answer 2

I've made this function to handle the URL:

 <?php
     function curPageURL()
     {
         $pageURL = 'http';
         if ($_SERVER["HTTPS"] == "on") {$pageURL .= "s";}
         $pageURL .= "://";
         if ($_SERVER["SERVER_PORT"] != "80") {
             $pageURL .=
             $_SERVER["SERVER_NAME"].":".$_SERVER["SERVER_PORT"].$_SERVER["REQUEST_URI"];
         }
         else {
             $pageURL .= $_SERVER["SERVER_NAME"].$_SERVER["REQUEST_URI"];
         }
         return $pageURL;
     }
 ?>

Answer 3

This is the solution for your problem:

//Fetch page URL by this

$url = $_SERVER['REQUEST_URI'];
echo "$url<br />";

//It will print
//fetch host by this

$host=$_SERVER['HTTP_HOST'];
echo "$host<br />";

//You can fetch the full URL by this

$fullurl = "http://".$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];
echo $fullurl;

Answer 4

Have a look at $_SERVER['REQUEST_URI'], i.e.

$actual_link = "http://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";

(Note that the double quoted string syntax is perfectly correct)

If you want to support both HTTP and HTTPS, you can use

$actual_link = (isset($_SERVER['HTTPS']) && $_SERVER['HTTPS'] === 'on' ? "https" : "http") . "://$_SERVER[HTTP_HOST]$_SERVER[REQUEST_URI]";

Editor's note: using this code has security implications. The client can set HTTP_HOST and REQUEST_URI to any arbitrary value it wants.

Answer 5

    public static function getCurrentUrl($withQuery = true)
    {
        $protocol = (!empty($_SERVER['HTTPS']) && strtolower($_SERVER['HTTPS']) !== 'off')
        or (isset($_SERVER['HTTP_X_FORWARDED_PROTO']) && strtolower($_SERVER['HTTP_X_FORWARDED_PROTO']) === 'https')
        or (!empty($_SERVER['HTTP_FRONT_END_HTTPS']) && strtolower($_SERVER['HTTP_FRONT_END_HTTPS']) !== 'off')
        or (isset($_SERVER['SERVER_PORT']) && intval($_SERVER['SERVER_PORT']) === 443) ? 'https' : 'http';

        $uri = $protocol . '://' . $_SERVER['HTTP_HOST'] . $_SERVER['REQUEST_URI'];

        return $withQuery ? $uri : str_replace('?' . $_SERVER['QUERY_STRING'], '', $uri);
    }

Answer 6

HTTP_HOST and REQUEST_URI must be in quotes, otherwise it throws an error in PHP 7.2

Use:

$actual_link = 'https://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];

If you want to support both HTTP and HTTPS:

$actual_link = (isset($_SERVER['HTTPS']) ? 'https' : 'http').'://'.$_SERVER['HTTP_HOST'].$_SERVER['REQUEST_URI'];