Starting python debugger automatically on error

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南方客
南方客 2020-11-27 08:44

This is a question I have wondered about for quite some time, yet I have never found a suitable solution. If I run a script and I come across, let\'s say an IndexError, pyth

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  • 2020-11-27 09:29

    Put a breakpoint inside the constructor of topmost exception class in the hierarchy, and most of the times you will see where the error was raised.

    Putting a breakpoint means whatever you want it to mean : you can use an IDE, or pdb.set_trace, or whatever

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  • 2020-11-27 09:30

    If you are using ipython, after launching type %pdb

    In [1]: %pdb
    Automatic pdb calling has been turned ON
    
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  • 2020-11-27 09:33

    If you are running a module:

    python -m mymodule
    

    And now you want to enter pdb when an exception occurs, do this:

    PYTHONPATH="." python -m pdb -c c mymodule/__main__.py
    

    (or extend your PYTHONPATH). The PYTHONPATH is needed so that the module is found in the path, since you are running the pdb module now.

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  • 2020-11-27 09:35

    IPython makes this simple on the command line:

    python myscript.py arg1 arg2
    

    can be rewritten to

    ipython --pdb myscript.py -- arg1 arg2
    

    Or, similarly, if calling a module:

    python -m mymodule arg1 arg2
    

    can be rewritten to

    ipython --pdb -m mymodule -- arg1 arg2
    

    Note the -- to stop IPython from reading the script's arguments as its own.

    This also has the advantage of invoking the enhanced IPython debugger (ipdb) instead of pdb.

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  • 2020-11-27 09:36

    You can use traceback.print_exc to print the exceptions traceback. Then use sys.exc_info to extract the traceback and finally call pdb.post_mortem with that traceback

    import pdb, traceback, sys
    
    def bombs():
        a = []
        print a[0]
    
    if __name__ == '__main__':
        try:
            bombs()
        except:
            extype, value, tb = sys.exc_info()
            traceback.print_exc()
            pdb.post_mortem(tb)
    

    If you want to start an interactive command line with code.interact using the locals of the frame where the exception originated you can do

    import traceback, sys, code
    
    def bombs():
        a = []
        print a[0]
    
    if __name__ == '__main__':
        try:
            bombs()
        except:
            type, value, tb = sys.exc_info()
            traceback.print_exc()
            last_frame = lambda tb=tb: last_frame(tb.tb_next) if tb.tb_next else tb
            frame = last_frame().tb_frame
            ns = dict(frame.f_globals)
            ns.update(frame.f_locals)
            code.interact(local=ns)
    
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  • 2020-11-27 09:39

    If you are using the IPython environment, you can just use the %debug and the shell will take you back to the offending line with the ipdb environment for inspections etc. Another option as pointed above is to use the iPython magic %pdb which effectively does the same.

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