fs.readdir ignore directories

Question

I would like to scan the folder, but ignore all the folders/directories that are included in it. All I have in the (C:/folder/) are .txt files and other folders, I just want to

Answer 1

Use fs.readdir or fs.readdirSync method with options { withFileTypes: true } and then do filtration using dirent.isFile (requires Node 10.10+).

Sync version

const fs = require('fs');
const dirents = fs.readdirSync(DIRECTORY_PATH, { withFileTypes: true });
const filesNames = dirents
    .filter(dirent => dirent.isFile())
    .map(dirent => dirent.name);
// use filesNames

Async version (with async/await, requires Node 11+)

import { promises as fs } from 'fs';

async function listFiles(directory) {
    const dirents = await fs.readdir(directory, { withFileTypes: true });
    return dirents
        .filter(dirent => dirent.isFile())
        .map(dirent => dirent.name);
}

Async version (with callbacks)

const fs = require('fs');
fs.readdir(DIRECTORY_PATH, { withFileTypes: true }, (err, dirents) => {
    const filesNames = dirents
        .filter(dirent => dirent.isFile())
        .map(dirent => dirent.name);
    // use filesNames
});

Answer 2

Please See diraria's answer as it is more complete: my answer only works if ALL filenames contain a '.txt' extension.

why not just filter out files that end in ".txt"?

var fs = require("fs")
fs.readdirSync("./").filter(function(file) {
    if(file.indexOf(".txt")>-1)console.log(file)
})

I should have added previously that to get an array of these files you need to return them to an array as shown below.

var fs = require("fs")
let text_file_array = fs.readdirSync("./").filter(function(file) {
    if(file.indexOf(".txt")>-1) return file;
})