Merge two maps, summing values for same keys in C++

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遇见更好的自我 2021-02-07 22:20

I have two std::map maps and wish to merge them into a third map like this: if the same key is found in both maps, create a pair in the third map wi

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  • 2021-02-07 22:40

    Here is an example how to do the task with using std::accumulate

    #include <iostream>
    #include <map>
    #include <numeric>
    
    int main() 
    {
        std::map<int, int> m1 = { { 1, 1 }, { 2, 2 }, { 3, 3 }, { 4, 4 } }; 
        std::map<int, int> m2 = { { 2, 5 }, { 3, 1 }, { 5, 5 } };
    
        for ( const auto &p : m1 ) 
        {
            std::cout << "{ " << p.first << ", " << p.second << " } ";
        }
    
        std::cout << std::endl;
    
        for ( const auto &p : m2 ) 
        {
            std::cout << "{ " << p.first << ", " << p.second << " } ";
        }
    
        std::cout << std::endl;
    
        std::map<int, int> m3 = std::accumulate( m1.begin(), m1.end(), std::map<int, int>(),
            []( std::map<int, int> &m, const std::pair<const int, int> &p )
            {
                return ( m[p.first] +=p.second, m );
            } );
    
        m3 = std::accumulate( m2.begin(), m2.end(), m3,
            []( std::map<int, int> &m, const std::pair<const int, int> &p )
            {
                return ( m[p.first] +=p.second, m );
            } );
    
        for ( const auto &p : m3 ) 
        {
            std::cout << "{ " << p.first << ", " << p.second << " } ";
        }
    
        std::cout << std::endl;
    
        return 0;
    }
    

    The output is

    { 1, 1 } { 2, 2 } { 3, 3 } { 4, 4 } 
    { 2, 5 } { 3, 1 } { 5, 5 } 
    { 1, 1 } { 2, 7 } { 3, 4 } { 4, 4 } { 5, 5 } 
    

    In fact only for the second map there is a need to use std::accumulate. The first map can be simply copied or assigned to m3.

    For example

        std::map<int, int> m3 = m1;
        m3 = std::accumulate( m2.begin(), m2.end(), m3,
            []( std::map<int, int> &m, const std::pair<const int, int> &p )
            {
                return ( m[p.first] +=p.second, m );
            } );
    
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  • 2021-02-07 22:47

    An overly generic solution inspired by std::set_union. Unlike the first suggested answer, this should run in O(n) instead of O(n log n).

    Edit: it's still O(n log n) because of insertions into the final map.

    #include <map>
    #include <iostream>
    #include <iterator>
    #include <algorithm>
    
    template<class InputIterT1, class InputIterT2, class OutputIterT, class Comparator, class Func>
    OutputIterT merge_apply(
        InputIterT1 first1, InputIterT1 last1,
        InputIterT2 first2, InputIterT2 last2,
        OutputIterT result, Comparator comp, Func func) {
      while (true)
      {
        if (first1 == last1) return std::copy(first2, last2, result);
        if (first2 == last2) return std::copy(first1, last1, result);
    
        if (comp(*first1, *first2) < 0) {
          *result = *first1;
          ++first1;
        } else if (comp(*first1, *first2) > 0) {
          *result = *first2;
          ++first2;
        } else { 
          *result = func(*first1, *first2);
          ++first1;
          ++first2; 
        }   
        ++result;
      }
    }
    
    template<class T>
    int compare_first(T a, T b) {
      return a.first - b.first;
    }
    
    template<class T>
    T sum_pairs(T a, T b) {
      return std::make_pair(a.first, a.second + b.second);
    }
    
    using namespace std;
    int main(int argc, char **argv) {
      map<int,int> a,b,c;
    
      a[1] = 10; 
      a[2] = 11; 
    
      b[2] = 100;
      b[3] = 101;
    
      merge_apply(a.begin(), a.end(), b.begin(), b.end(), inserter(c, c.begin()),
          compare_first<pair<int, int> >, sum_pairs<pair<int, int> >); 
    
      for (auto item : c)                                                                                                       
        cout << item.first << " " << item.second << endl;
    }
    
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  • 2021-02-07 23:00

    I don't think it will be easy (if not impossible) to find a suitable std::algorithm that serves the purpose.

    The easiest way would be to first make a copy of map1 to map_result.

    Then iterate through map2 and see if any key already exists in map_result then add the values, else add the key_value pair to map_result.

    std::map<int,int> map_result( map1 );
    
    for (auto it=map2.begin(); it!=map2.end(); ++it) {
      if ( map_result[it->first] )
        map_result[it->first] += it->second;
      else
        map_result[it->first] = it->second;
    }
    
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