Convert string from __DATE__ into a time_t

Question

I\'m trying to convert the string produced from the __DATE__ macro into a time_t. I don\'t need a full-blown date/time parser, something that only han

Answer 1

Jerry's function looks great. Here's my attempt.. I threw in the __TIME__ as well.

#include <iostream>
#include <sstream>

using namespace std;

time_t time_when_compiled()
{
    string datestr = __DATE__;
    string timestr = __TIME__;

    istringstream iss_date( datestr );
    string str_month;
    int day;
    int year;
    iss_date >> str_month >> day >> year;

    int month;
    if     ( str_month == "Jan" ) month = 1;
    else if( str_month == "Feb" ) month = 2;
    else if( str_month == "Mar" ) month = 3;
    else if( str_month == "Apr" ) month = 4;
    else if( str_month == "May" ) month = 5;
    else if( str_month == "Jun" ) month = 6;
    else if( str_month == "Jul" ) month = 7;
    else if( str_month == "Aug" ) month = 8;
    else if( str_month == "Sep" ) month = 9;
    else if( str_month == "Oct" ) month = 10;
    else if( str_month == "Nov" ) month = 11;
    else if( str_month == "Dec" ) month = 12;
    else exit(-1);

    for( string::size_type pos = timestr.find( ':' ); pos != string::npos; pos = timestr.find( ':', pos ) )
        timestr[ pos ] = ' ';
    istringstream iss_time( timestr );
    int hour, min, sec;
    iss_time >> hour >> min >> sec;

    tm t = {0};
    t.tm_mon = month-1;
    t.tm_mday = day;
    t.tm_year = year - 1900;
    t.tm_hour = hour - 1;
    t.tm_min = min;
    t.tm_sec = sec;
    return mktime(&t);
}

int main( int, char** )
{
    cout << "Time_t when compiled: " << time_when_compiled() << endl;
    cout << "Time_t now: " << time(0) << endl;

    return 0;
}