What I am looking is equivalent of Document.parse()
in golang, that allows me create bson from json directly? I do not want to create intermediate Go structs for marshal
mongo-go-driver
has a function bson.UnmarshalExtJSON
that does the job.
Here's the example:
var doc interface{}
err := bson.UnmarshalExtJSON([]byte(`{"foo":"bar"}`), true, &doc)
if err != nil {
// handle error
}
The gopkg.in/mgo.v2/bson package has a function called UnmarshalJSON which does exactly what you want.
The data
parameter should hold you JSON string as []byte
value.
func UnmarshalJSON(data []byte, value interface{}) error
UnmarshalJSON unmarshals a JSON value that may hold non-standard syntax as defined in BSON's extended JSON specification.
Example:
var bdoc interface{}
err = bson.UnmarshalJSON([]byte(`{"id": 1,"name": "A green door","price": 12.50,"tags": ["home", "green"]}`),&bdoc)
if err != nil {
panic(err)
}
err = c.Insert(&bdoc)
if err != nil {
panic(err)
}
There is no longer a way to do this directly with supported libraries (e.g. the mongo-go-driver). You would need to write your own converter based on the bson spec.