7zip Commands from Python

Question

There is a post on this topic already, but it does not have an explicit answer to the fundamental question which I am re-asking here:

How do you make 7zip commands from

Answer 1

import subprocess
cmd = ['7z', 'a', 'Test.7z', 'Test', '-mx9']
sp = subprocess.Popen(cmd, stderr=subprocess.STDOUT, stdout=subprocess.PIPE)

Answer 2

You can wrap it as a function using the following:

import subprocess

def sevenzip(filename, zipname, password):
    print("Password is: {}".format(password))
    system = subprocess.Popen(["7z", "a", zipname, filename, "-p{}".format(password)])
    return(system.communicate())

This definitely works as I've tried and tested it. If you want to tweak it i.e. to Extract files then you can use the following:

def extractfiles(zipname):
    system = subprocess.Popen(["7z", "e", zipname])
    return(system.communicate())

Give this a try and lemme know how you get on.

Bear in mind this is for Linux. In Windows, swap "7z" with "C:\Program Files\7-Zip\7z.exe" (i think that's the right location).

Answer 3

The following one works for me, python 3.5.2, windows8.1, 7z path added to system

    rc = subprocess.call(['7z', 'a', output_filename + '.zip', '-mx9', '-pSecret^)'] + [src_folder + '/'])

With two parameters, -mx9 means max compression, -pSecret^) means password is "Secret^)" , "^" is escape for ")"for windows system, but when you unzip, it will need type in the "^".

Without "^", windows system will not apply the password when 7z.exe creating the zip file.

Also, if you want to use "-mhe" switch, you need file format in 7z instead of zip.