MongoDB find and remove - the fastest way

Question

I have a quick question, what is the fast way to grab and delete an object from a mongo collection. Here is the code, I have currently:

$cursor = $coll->find(         


        

Answer 1

Peter, It's hard to say what the best solution is here without understanding all the context - but one approach which you could use is findAndModify. This will query for a single document and return it, and also apply an update to it.

You could use this to find a document to process and simultaneously modify a "status" field to mark it as being processed, so that other workers can recognize it as such and ignore it.

There is an example here that may be useful: http://docs.mongodb.org/manual/reference/command/findAndModify/

Answer 2

I make a new answer to remark the fact:

As commented by @peterscodeproblems in the accepted answer. The native way to this in mongodb right now is to use the

findAndModify(query=<document>, remove=True)

As pointed out by the documentation.

As it is native, and atomic, I expect this to be the faster way to do this.

Answer 3

Use the findAndRemove function as documented here: http://api.mongodb.org/java/current/com/mongodb/DBCollection.html

The findAndRemove function retrieve and object from the mongo database and delete it in a single (atomic) operation.

findAndRemove(query, sort[, options], callback)

• The query object is used to retrieve the object from the database (see collection.find())
• The sort parameter is used to sort the results (in case many where found)

Answer 4

I am new to mongodb and not entirely sure what your query is trying to do, but here is how I would do it

# suppose database is staging
# suppose collection is data
use staging
db.data.remove(<your_query_criteria>)

where is a map and can contain any search criteria you want

Not sure if this would help you.