void cast of argc and argv

Question

I\'m looking at a piece of C++ code, and the first line in the main function caught my attention:

int main(int argc, const char* argv[]) {
    (void)argc; (void)         


        

Answer 1

"Could it be to stop the compiler from complaining about unused variables?"

yes

Answer 2

Yes, it is to prevent the compiler from complaining about unused variables. In this case a better way would be:

int main(int, char**) {
    ...
}

Leaving the parameters unnamed tells the compiler that they're there but are not used.

Answer 3

If you set -Werror option, the compiler makes all warnings into errors, stopping compilation. It's a good practice set -Wall -Werror to check all inconsistences.

Answer 4

Yes, it's exactly to tell the compiler not to complain about unused variables.