Validation of a Password - Python

Question

So I have to create code that validate whether a password:

• Is at least 8 characters long
• Contains at least 1 number
• Contains at least 1

Answer 1

''' Minimum length is 5;
 - Maximum length is 10;
 - Should contain at least one number;
 - Should contain at least one special character (such as &, +, @, $, #, %, etc.);
 - Should not contain spaces.
'''

import string

def checkPassword(inputStr):
    if not len(inputStr):
        print("Empty string was entered!")
        exit(0)

    else:
        print("Input:","\"",inputStr,"\"")

    if len(inputStr) < 5 or len(inputStr) > 10:
        return False

    countLetters = 0
    countDigits = 0
    countSpec = 0
    countWS = 0

    for i in inputStr:
        if i in string.ascii_uppercase or i in string.ascii_lowercase:
             countLetters += 1
        if i in string.digits:
            countDigits += 1
        if i in string.punctuation:
            countSpec += 1
        if i in string.whitespace:
            countWS += 1

    if not countLetters:
        return False
    elif not countDigits:
        return False
    elif not countSpec:
        return False
    elif countWS:
        return False
    else:
        return True


print("Output: ",checkPassword(input()))

With Regex

s = input("INPUT: ")
print("{}\n{}".format(s, 5 <= len(s) <= 10 and any(l in "0123456789" for l in s) and any(l in "!\"#$%&'()*+,-./:;<=>?@[\]^_`{|}~" for l in s) and not " " in s))

Module import

from string import digits, punctuation

def validate_password(p):
    if not 5 <= len(p) <= 10:
        return False

    if not any(c in digits for c in p):
        return False

    if not any(c in punctuation for c in p):
        return False

    if ' ' in p:
        return False

    return True

for p in ('DJjkdklkl', 'John Doe'
, '$kldfjfd9'):
    print(p, ': ', ('invalid', 'valid')[validate_password(p)], sep='')

Answer 2

password.isdigit() does not check if the password contains a digit, it checks all the characters according to:

str.isdigit(): Return true if all characters in the string are digits and there is at least one character, false otherwise.

password.isupper() does not check if the password has a capital in it, it checks all the characters according to:

str.isupper(): Return true if all cased characters in the string are uppercase and there is at least one cased character, false otherwise.

For a solution, please check the question and accepted answer at check if a string contains a number.

You can build your own hasNumbers()-function (Copied from linked question):

def hasNumbers(inputString):
    return any(char.isdigit() for char in inputString)

and a hasUpper()-function:

def hasUpper(inputString):
    return any(char.isupper() for char in inputString)

Answer 3

Maybe you can use regex expression:

re.search(r"[A-Z]", password)

Check uppercase letters.

re.search(r"[0-9]", password)

Check digits in password.

Answer 4

Or you can use this to check if it got at least one digit:

min(passwd).isdigit()

Answer 5

uppercase_letter = ['A', 'B','C', 'D','E','F','G','H','I','J','K','L','M','N','O',
            'P','Q','R','S','T','U','V','W','X','Y','Z']

number = [1, 2, 3, 4, 5, 6, 7, 8, 9, 0]

import re

info ={}

while True:

    user_name = input('write your username: ')

    if len(user_name) > 15:
        print('username is too long(must be less than 16 character)')
    elif len(user_name) < 3 :
        print('username is short(must be more than 2 character)')
    else:
        print('your username is', user_name)
        break


while True:   

    password= input('write your password: ')

    if len(password) < 8 :
        print('password is short(must be more than 7 character)')

    elif len(password) > 20:
        print('password is too long(must be less than 21 character)') 

    elif re.search(str(uppercase_letter), password ) is None :
        print('Make sure your password has at least one uppercase letter in it')

    elif re.search(str(number), password) is None :
        print('Make sure your password has at least number in it')

    else:
        print('your password is', password)
        break

info['user name'] = user_name

info['password'] = password

print(info)