Python inline elif possible?

Question

\'Hello \' + (\'there\' if name is None else name)

Is the equivalent of

msg = \'Hello \'
if name is None:
    msg += \'there\'
else:
          


        

Answer 1

Do not do it.

Do this instead:

% python -m this | sed 's/^R.*/======>&<======/'

EDIT: For reference, here is how I would refactor this code...

Whenever I see elif, I think dict.

#!/usr/bin/env python

class Shrink(object):
    types = {
            'p': 'Pointer',
            'v': 'Value',
            }

    def shrink_this(self):
        return "'Modify %s By %s'" % (
                self.types.get(self.register, 'Unknown'), self.delta)

import unittest
class TestShrink(unittest.TestCase):

    def test_p(self):
        s = Shrink();
        s.register = 'p'
        s.delta = 'delta'
        self.assertEquals("'Modify Pointer By delta'", s.shrink_this())

    def test_u(self):
        s = Shrink();
        s.register = 'u'
        s.delta = 'echo'
        self.assertEquals("'Modify Unknown By echo'", s.shrink_this())

    def test_v(self):
        s = Shrink();
        s.register = 'v'
        s.delta = 'foxtrot'
        self.assertEquals("'Modify Value By foxtrot'", s.shrink_this())

if __name__ == '__main__':
    unittest.main()

Were you to need to add r for reference or pp for pointer-to-pointer, only types requires a change and your code remains readable.

Readability counts.