I want to match a regular expression special character, \\^$.?*|+()[{
. I tried:
x <- \"a[b\"
grepl(\"[\", x)
## Error: invalid regular expre
I think the easiest way to match the characters like
\^$.?*|+()[
are using character classes from within R. Consider the following to clean column headers from a data file, which could contain spaces, and punctuation characters:
> library(stringr)
> colnames(order_table) <- str_replace_all(colnames(order_table),"[:punct:]|[:space:]","")
This approach allows us to string character classes to match punctation characters, in addition to whitespace characters, something you would normally have to escape with \\
to detect. You can learn more about the character classes at this cheatsheet below, and you can also type in ?regexp
to see more info about this.
https://www.rstudio.com/wp-content/uploads/2016/09/RegExCheatsheet.pdf
R treats backslashes as escape values for character constants. (... and so do regular expressions. Hence the need for two backslashes when supplying a character argument for a pattern. The first one isn't actually a character, but rather it makes the second one into a character.) You can see how they are processed using cat.
y <- "double quote: \", tab: \t, newline: \n, unicode point: \u20AC"
print(y)
## [1] "double quote: \", tab: \t, newline: \n, unicode point: €"
cat(y)
## double quote: ", tab: , newline:
## , unicode point: €
Further reading: Escaping a backslash with a backslash in R produces 2 backslashes in a string, not 1
To use special characters in a regular expression the simplest method is usually to escape them with a backslash, but as noted above, the backslash itself needs to be escaped.
grepl("\\[", "a[b")
## [1] TRUE
To match backslashes, you need to double escape, resulting in four backslashes.
grepl("\\\\", c("a\\b", "a\nb"))
## [1] TRUE FALSE
The rebus
package contains constants for each of the special characters to save you mistyping slashes.
library(rebus)
OPEN_BRACKET
## [1] "\\["
BACKSLASH
## [1] "\\\\"
For more examples see:
?SpecialCharacters
Your problem can be solved this way:
library(rebus)
grepl(OPEN_BRACKET, "a[b")
You can also wrap the special characters in square brackets to form a character class.
grepl("[?]", "a?b")
## [1] TRUE
Two of the special characters have special meaning inside character classes: \
and ^
.
Backslash still needs to be escaped even if it is inside a character class.
grepl("[\\\\]", c("a\\b", "a\nb"))
## [1] TRUE FALSE
Caret only needs to be escaped if it is directly after the opening square bracket.
grepl("[ ^]", "a^b") # matches spaces as well.
## [1] TRUE
grepl("[\\^]", "a^b")
## [1] TRUE
rebus
also lets you form a character class.
char_class("?")
## <regex> [?]
If you want to match all punctuation, you can use the [:punct:]
character class.
grepl("[[:punct:]]", c("//", "[", "(", "{", "?", "^", "$"))
## [1] TRUE TRUE TRUE TRUE TRUE TRUE TRUE
stringi
maps this to the Unicode General Category for punctuation, so its behaviour is slightly different.
stri_detect_regex(c("//", "[", "(", "{", "?", "^", "$"), "[[:punct:]]")
## [1] TRUE TRUE TRUE TRUE TRUE FALSE FALSE
You can also use the cross-platform syntax for accessing a UGC.
stri_detect_regex(c("//", "[", "(", "{", "?", "^", "$"), "\\p{P}")
## [1] TRUE TRUE TRUE TRUE TRUE FALSE FALSE
Placing characters between \\Q
and \\E
makes the regular expression engine treat them literally rather than as regular expressions.
grepl("\\Q.\\E", "a.b")
## [1] TRUE
rebus
lets you write literal blocks of regular expressions.
literal(".")
## <regex> \Q.\E
Regular expressions are not always the answer. If you want to match a fixed string then you can do, for example:
grepl("[", "a[b", fixed = TRUE)
stringr::str_detect("a[b", fixed("["))
stringi::stri_detect_fixed("a[b", "[")