#include
#include
#include
int main()
{
struct emp
{
struct address
{
int a;
The reason why the compiler is showing the warning is because it doesn't see a name for the variable of type address
you defined for the emp
struct, even though you do declare something using address
on the next line, but I guess the compiler is not smart enough to figure that out.
As you showed, this produces a warning:
struct emp {
struct address {}; // This statement doesn't declare any variable for the emp struct.
struct address a1;
};
But not this:
struct emp {
struct address {} a1; // This statement defines the address struct and the a1 variable.
};
Or this:
struct address {};
struct emp {
struct address a1; //the only statement declare a variable of type struct address
};
The struct emp {}
doesn't show any warnings since this statement is not inside a struct defintion block. If you did put it inside one of those then the compiler will show a warning for that as well. The following will show two warnings:
struct emp {
struct phone {};
struct name {};
};
Going to also throw this out there that this error may also show up if you don't properly forward declare types found in other namespaces.
https://stackoverflow.com/a/19001722/1330381
Example
namespace A {
// forward declarations
namespace X {
namespace Y {
class MyType;
}
}
namespace B {
class Foo() {
void methodBar(const X::Y::MyType& mt);
}
}
The reason the warning is displayed is that the first excerpt is not proper C - it has a constraint violation that a standards-compliant C compiler must produce a diagnostisc message for. It violates the C11 6.7.2.1p2:
Constraints
- A struct-declaration that does not declare an anonymous structure or anonymous union shall contain a struct-declarator-list.
Meaning that it is OK to write
struct foo {
struct {
int a;
};
};
since the inner struct
declares an anonymous structure, i.e. it is not named.
But in your example the struct address
has a name - address
- and therefore it must have a declarator list after the closing brace - declarator list being for example a1
as in your example, or more complex foo, *bar, **baz[23][45]
.
The syntax of a structure definition is:
struct identifier {
type member_name;
// ...
};
If you add an identifier just after the closing curly brace, you're declaring a variable with that defined struct.
In your first example the compiler consider the address
struct as member type. it's like if you writes:
struct identifier {
type ; // No member name is specified
type a1;
// ...
}
But in the second example you specified the member name:
struct identifier {
type a1; // Member name specified
// ...
}
And here is an example of the warning: http://ideone.com/KrnYiE.