Counting repeated elements in an integer array

Question

I have an integer array crr_array and I want to count elements, which occur repeatedly. First, I read the size of the array and initialize it with numbers read

Answer 1

public class DuplicationNoInArray {

    /**
     * @param args
     *            the command line arguments
     */
    public static void main(String[] args) throws Exception {
        int[] arr = { 1, 2, 3, 4, 5, 1, 2, 8 };
        int[] result = new int[10];
        int counter = 0, count = 0;
        for (int i = 0; i < arr.length; i++) {
            boolean isDistinct = false;
            for (int j = 0; j < i; j++) {
                if (arr[i] == arr[j]) {
                    isDistinct = true;
                    break;
                }
            }
            if (!isDistinct) {
                result[counter++] = arr[i];
            }
        }
        for (int i = 0; i < counter; i++) {
            count = 0;
            for (int j = 0; j < arr.length; j++) {
                if (result[i] == arr[j]) {
                    count++;
                }

            }
            System.out.println(result[i] + " = " + count);

        }
    }
}

Answer 2

public static void main(String[] args) {
    Scanner input=new Scanner(System.in);
    int[] numbers=new int[5];
    String x=null;
    System.out.print("enter the number 10:"+"/n");
    for(int i=0;i<5;i++){
        numbers[i] = input.nextInt();
    }
    System.out.print("Numbers  :  count"+"\n");
    int count=1;
    Arrays.sort(numbers);
    for(int z=0;z<5;z++){
        for(int j=0;j<z;j++){
            if(numbers[z]==numbers[j] & j!=z){
                count=count+1;
            }
        }
        System.out.print(numbers[z]+" - "+count+"\n");
        count=1;

    }

Answer 3

package jaa.stu.com.wordgame;

/**
 * Created by AnandG on 3/14/2016.
 */
public final class NumberMath {
    public static boolean isContainDistinct(int[] arr) {

        boolean isDistinct = true;
        for (int i = 0; i < arr.length; i++)

        {

            for (int j = 0; j < arr.length; j++) {
                if (arr[i] == arr[j] && i!=j) {
                    isDistinct = false;
                    break;
                }
            }

        }
        return isDistinct;
    }
    public static boolean isContainDistinct(float[] arr) {

        boolean isDistinct = true;
        for (int i = 0; i < arr.length; i++)

        {

            for (int j = 0; j < arr.length; j++) {
                if (arr[i] == arr[j] && i!=j) {
                    isDistinct = false;
                    break;
                }
            }

        }
        return isDistinct;
    }
    public static boolean isContainDistinct(char[] arr) {

        boolean isDistinct = true;
        for (int i = 0; i < arr.length; i++)

        {

            for (int j = 0; j < arr.length; j++) {
                if (arr[i] == arr[j] && i!=j) {
                    isDistinct = false;
                    break;
                }
            }

        }
        return isDistinct;
    }
    public static boolean isContainDistinct(String[] arr) {

        boolean isDistinct = true;
        for (int i = 0; i < arr.length; i++)

        {

            for (int j = 0; j < arr.length; j++) {
                if (arr[i] == arr[j] && i!=j) {
                    isDistinct = false;
                    break;
                }
            }

        }
        return isDistinct;
    }
    public static int[] NumberofRepeat(int[] arr) {

        int[] repCount= new int[arr.length];
        for (int i = 0; i < arr.length; i++)

        {

            for (int j = 0; j < arr.length; j++) {
                if (arr[i] == arr[j] ) {
                    repCount[i]+=1;
                }
            }

        }
        return repCount;
    }
}


call  by NumberMath.isContainDistinct(array) for find is it contains repeat or not

call by int[] repeat=NumberMath.NumberofRepeat(array) for find repeat count. Each location contains how many repeat corresponding value of array...

Answer 4

for (int i = 0; i < x.length; i++) {

    for (int j = i + 1; j < x.length; j++) {

        if (x[i] == x[j]) {
            y[i] = x[i];
            times[i]++;
        }

    }

}

Answer 5

 public static void duplicatesInteger(int arr[]){
    Arrays.sort(arr);       
    int count=0;
    Set s=new HashSet();
    for(int i=0;i<=arr.length-1;i++){
        for(int j=i+1;j<=arr.length-1;j++){
            if(arr[i]==arr[j] && s.add(arr[i])){
                count=count+1;              
                                }
        }
        System.out.println(count);
    }
}

Answer 6

public class FindRepeatedNumbers 
{
 public static void main(String[] args) 
    {
     int num[]={1,3,2,4,1,2,4,6,7,5};
           Arrays.sort(num);

  for(int j=1;j<num.length;j++)
      {
       if(num[j]==num[j-1])
    {
            System.out.println(num[j]);

       }
   }

       }
     }