If a function returns an UnsafeMutablePointer is it our responsibility to destroy and dealloc?

Question

For example if I were to write this code:

var t = time_t()
time(&t)
let x = localtime(&t) // returns UnsafeMutablePointer
        
println("         


        

Answer 1

From Swift library UnsafeMutablePointer<T>

A pointer to an object of type T. This type provides no automated memory management, and therefore the user must take care to allocate and free memory appropriately.

The pointer can be in one of the following states:

• memory is not allocated (for example, pointer is null, or memory has been deallocated previously);
• memory is allocated, but value has not been initialized;
• memory is allocated and value is initialized.

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struct UnsafeMutablePointer<T> : RandomAccessIndexType, Hashable, NilLiteralConvertible { /**/}

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